SQL SUM OVER PARTITION BY 计算组的百分比

Question

谁能告诉我为什么下面的代码无法编译？

我正在尝试计算 'M3' 标记的交易占整个批次的百分比。

我认为如果只有一批就足够容易了，但有时会有多批。

完整代码如下：

SELECT 
    [Batch],
    [DocNum],
    [Date],
    [Time],
    [Location],
    [ItemCode],
    [Brand],
    [Quantity],
    CASE
        WHEN [Variance] IS NULL
            THEN ''
        ELSE [Variance]
    END AS [Variance],
    CASE
        WHEN [Comments] IS NULL
            THEN ''
        ELSE [Comments]
    END AS [Comments],
    CASE
        WHEN [Variance] = 'M3'
            THEN(
                (
                (SELECT
                    ABS([Quantity])
                  FROM #BatchReport
                  WHERE [Variance] = 'M3')
                 / 
                 (SELECT
                     SUM([Quantity])
                     FROM #BatchReport
                     WHERE [Quantity] > 0)
                ) * 100) OVER (PARTITION BY [Batch])
        ELSE '0'
    END AS [Pct Loss],                          
    SUM([Quantity]) OVER (PARTITION BY [Batch]) AS [Difference],
    ((SUM([Quantity]) - MAX([Quantity])) * 100) / MAX([Quantity]) OVER (PARTITION BY [Batch]) AS [Pct Difference]


FROM #BatchReport
WHERE [DocNum] IS NOT NULL
GROUP BY [Batch], [DocNum], [Date], [Time], [Variance], [Brand], [Comments], [Quantity], [Location], [ItemCode]
ORDER BY [Batch], [Date], [Time]

错误文本：Incorrect syntax near the keyword 'OVER'.

如果我删除这部分，错误就会消失：

CASE
        WHEN [Variance] = 'M3'
            THEN(
                (
                (SELECT
                    ABS([Quantity])
                  FROM #BatchReport
                  WHERE [Variance] = 'M3')
                 / 
                 (SELECT
                     SUM([Quantity])
                     FROM #BatchReport
                     WHERE [Quantity] > 0)
                ) * 100) OVER (PARTITION BY [Batch])
        ELSE '0'
    END AS [Pct Loss]

类似于我想要得到的样例：

谢谢！

Answer 1

你的表达逻辑基本看不懂。我猜您想要 "M3" 值与总体值之间的某种比率。我最好的猜测是：

(100.0 * SUM(CASE WHEN [Variance] = 'M3' THEN ABS([Quantity]) END) /
 SUM(CASE WHEN Quantity > 0 THEN Quantity END ) OVER (PARTITION BY Batch)
) as [Pct Loss]

但是，您的 GROUP BY 非常复杂，如果您的查询符合您的要求，我会感到很惊讶。我认为你应该 post 另一个关于样本数据和预期结果的问题。

SQL SUM OVER PARTITION BY 计算组的百分比

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