在 javascript 中获取多维数组中的索引

Question

这个问题正在跟进，

我试过这个答案，

var    a1 = [["present",["John","Josh","Jay"]],["absent",["May","Mary","Mary Jane"]]],
   a2 = [["J",["John","Josh","Jay"]],["M",["May","Mary","Mary Jane"]],["S",["Sally","Sam","Sammy Davis"]]],
getStatus = (a,n) => a.find(e => e[1].indexOf(n) !== -1)[0],
getIndex = (a,n) => a.findIndex(e => e[1].indexOf(n) !== -1);

console.log(getStatus(a1,"Mary"));
console.log(getIndex(a2,"Sammy Davis"));

这是可行的，但存在问题。如果给定的字符串不在数组中怎么办？如何处理？如果有多个索引具有给定字符串的值，如何获取所有索引？

例如，在a1中，

var a1 = ["present",["John","Josh","Jay"]],["absent",["May","Josh","Mary Jane"]]]

如何得到0,1？使用 getIndex()?

Answer 1

我不得不同意@Rob M. 的评论，但您仍然可以按照以下方式进行；

var    a1 = [["present",["John","Josh","Jay"]],["absent",["May","Mary","Mary Jane"]]],
       a2 = [["J",["John","Josh","Jay"]],["M",["May","Mary","Mary Jane"]],["S",["Sally","Sam","Sammy Davis"]]],
getStatus = (a,n) => a.find(e => e[1].indexOf(n) !== -1)[0],
 getIndex = (a,n) => { var x = -1;
                       return [a.findIndex(e => (x = e[1].indexOf(n), x !== -1)),x];
                     };
console.log(getIndex(a2,"May"));
console.log(getIndex(a2,"Sammy Davis"));
console.log(getIndex(a2,"Daniel"));

在 javascript 中获取多维数组中的索引

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