如何在 Laravel 5.1 中编写原始查询？

Question

我是 Laravel.I 的初学者，可以用原始格式编写查询 PHP.Now 我想用 Laravel 编写查询 framework.I 已阅读文档并尝试过：

原始 PHP:

SELECT count(*)/(TIMESTAMPDIFF(YEAR,'2016-01-01 00:00:00',now())+1) as avg from buyer  where created_at >= '2016-01-01 00:00:00';

尝试过 Laravel:

public function index(){
    //
    $yrUserReg = DB::table('buyer')
                    -> SELECT (DB::raw (count('*')/("TIMESTAMPDIFF(YEAR,'2016-01-01 00:00:00',now())+1"))) 
                    -> AS ('avg') 
                    -> WHERE ("created_at >= '2016-01-01 00:00:00'");
   return view('userflow',compact($yrUserReg));                 
}

但它抛出一个错误：Division by Zero。我找不到任何解决方案。提前致谢。任何帮助将不胜感激！！

Answer 1

这是完整的构建查询：

$yrUserReg =  DB::table('buyer')
                ->select(DB::raw("(count('*')/(TIMESTAMPDIFF(YEAR,'2016-01-01 00:00:00',now())+1)) as avg"))
                ->where('created_at', '>=', '2016-01-01 00:00:00')
                ->get();

如何在 Laravel 5.1 中编写原始查询？

How to write raw query in Laravel 5.1?

php

mysql

laravel

laravel-5.1