Derby

Question

我无法使用带有 spring 框架的 JdbcTemplate 获取最后插入 ID，在使用 last_insert_id() 函数之前，我已经搜索了很多其他方法，但无法使用它. 顺便说一下，我的 table 有

private static final String insertResponse =
        "INSERT INTO response (" +
        " idReceiver) " +
        "VALUES (?)";

public static void saveResponse(Response response, User user) {
    dataSource = getDataSource();



    JdbcTemplate template = new JdbcTemplate(dataSource);

     //"select id from users where username ='"+ user.getUsername +"'";
    // define query arguments
    Object[] params = new Object[] { 1 };
    int[] responseTypes = new int[] { Types.INTEGER };
    int row = template.update(insertResponse, params, responseTypes);
    if (row >0){
    SqlRowSet rowSet = template.queryForRowSet("SELECT LAST_INSERT_ID() AS id");
    int lastInsertedID=0;
    if (rowSet.next())
        lastInsertedID = rowSet.findColumn("id");
    System.out.println("last insert row is : "+lastInsertedID);
}

我的回复 table 是通过此命令创建的：

CREATE TABLE RESPONSE (
   ID INT NOT NULL PRIMARY KEY GENERATED ALWAYS AS IDENTITY 
   (START WITH 1, INCREMENT BY 1),
   idReceiver INT NOT NULL
 );

当我运行这段代码时，我的 JVM 说“嘿，伙计，你有这个例外： org.springframework.jdbc.BadSqlGrammarException:语句回调；错误 SQL 语法 [SELECT LAST_INSERT_ID() AS id]；嵌套异常是 java.sql.SQLSyntaxErrorException：语法错误：在第 1 行第 29 列遇到“”。

Answer 1

如果有人遇到我同样的问题，我已经解决了，按照这个answer..

    KeyHolder keyHolder = new GeneratedKeyHolder();
    template.update(
    new PreparedStatementCreator() {
        @Override
        public PreparedStatement createPreparedStatement(java.sql.Connection connection) throws SQLException {
             PreparedStatement ps =
            connection.prepareStatement(insertResponse, new String[] {"id"});
            ps.setInt(1, 1);
            return ps;
          }
        },
        keyHolder);

    System.out.println("last inserted id is "+keyHolder.getKey());

Derby - LAST_INSERT_ID() 不适用于 JDBC

Derby - LAST_INSERT_ID() doesn't work with JDBC

spring-jdbc