具有多个值的数据透视列

Question

Table #温度:

ID    Name        Hobbies
1     xxx          Reading
1     xxx          Sports
1     xxx          Dance
2     xyz          Dance
3     yyy          Swimming
3     yyy          Reading

现在，我希望结果集为：

ID   Name    Hobby1     Hobby2    Hobby3 
1    xxx     Reading    Sports    Dance         
2    xyz     Cooking                  
3    yyy     Coloring   Swimming

如何实现？我已经使用了多个兴趣爱好值，所以我不能硬编码。

Answer 1

因为你知道每个名字的最大爱好数你可以为每个名字生成行号并将其用于旋转

;with data as
(
SELECT row_number()over(partition by [ID] order by [Hobbies])rn,*
FROM   ( VALUES (1,'xxx','Reading'),
                (1,'xxx','Sports'),
                (1,'xxx','Dance'),
                (2,'xyz','Dance'),
                (3,'yyy','Swimming'),
                (3,'yyy','Reading')) tc ([ID], [Name], [Hobbies])
)
SELECT [ID],
       [Name],
       [Hobby1] = Max(CASE WHEN rn = 1 THEN [Hobbies] END),
       [Hobby2] = Max(CASE WHEN rn = 2 THEN [Hobbies] END),
       [Hobby3] = Max(CASE WHEN rn = 3 THEN [Hobbies] END)
FROM   data
GROUP  BY [ID],
          [Name]

结果：

╔════╦══════╦═════════╦══════════╦════════╗
║ ID ║ Name ║ Hobby1  ║  Hobby2  ║ Hobby3 ║
╠════╬══════╬═════════╬══════════╬════════╣
║  1 ║ xxx  ║ Dance   ║ Reading  ║ Sports ║
║  2 ║ xyz  ║ Dance   ║ NULL     ║ NULL   ║
║  3 ║ yyy  ║ Reading ║ Swimming ║ NULL   ║
╚════╩══════╩═════════╩══════════╩════════╝

Answer 2

像这样尝试

DECLARE @tbl TABLE(ID INT,Name VARCHAR(100),Hobbies VARCHAR(100));
INSERT INTO @tbl VALUES
 (1,'xxx','Reading')
,(1,'xxx','Sports')
,(1,'xxx','Dance')
,(2,'xyz','Dance')
,(3,'yyy','Swimming')
,(3,'yyy','Reading');

SELECT p.*
FROM
(
    SELECT tbl.*
          ,'Hobby' + CAST(ROW_NUMBER() OVER(PARTITION BY tbl.Name ORDER BY tbl.ID) AS VARCHAR(10)) AS ColumnName
    FROM @tbl AS tbl
) AS t
PIVOT
(
    MAX(Hobbies) FOR ColumnName IN(Hobby1,Hobby2,Hobby3,Hobby4 /*add more if needed*/)
) AS p

结果

ID  Name    Hobby1   Hobby2  Hobby3 Hobby4
1   xxx     Reading  Sports   Dance NULL
2   xyz     Dance    NULL     NULL  NULL
3   yyy     Swimming Reading  NULL  NULL

Answer 3

试试这个......

            select ID  , Name  ,  Hobby1    , Hobby2  ,  Hobby3 
             from
             (
             select 
            ID , Name,Hobbies, 
                case when Hobyno ='1' then 'Hobby1' 
                when Hobyno ='2' then 'Hobby2' 
                when Hobyno ='3' then 'Hobby3' 
                else null end as HobyNo 
            from

            (
             select   *,ROW_NUMBER() OVER ( PARTITION  BY id order by id ) HobyNo
              from   #temp
            )a
            where a.HobyNo <4  -- Add if you want more than 3 hobbie also edit case when
             )a 

            pivot
            (
              max(Hobbies)
              for Hobyno in ([Hobby1],[Hobby2],[Hobby3] )
            ) piv;

具有多个值的数据透视列

Pivot columns with multiple values

sql

sql-server

pivot