需要 SQL 查询平面结果集中的分层数据

Question

有一个table：PS_POSITION_TBL

position_nbr      reports_to              descr        
 038              143                     DIRECTOR 
 0418             143                     ADVISOR                        
 114              143                     DG                              
 346              114                     Manager                        
 202              114                     Lead

我们要在上面构建层次结构的想法

案例 1：038、0418 和 114 向 143 报告

案例 2：346 和 202 报告给 114

所以最高级别是 143 级，然后 038,0418,114 是 2 级，因为他们向 1 级报告，然后 346 和 202 是 3 级，他们属于 3 级存储桶，他们向 2 级报告

这些可以达到 8 级（最高）

我需要的是在 Oracle 中获取以下格式的数据的查询：

level1  level2   level3  level4 level5 level6 level7 level8      descr
 143                                                             CEO            
           038                                                   DIRECTOR        
           0418                                                  ADVISOR         
           114                                                   DG              
                    346                                          Manager         
                    202                                          Lead

Answer 1

以下查询将为您提供一个分层集，左填充 LEVEL:

SELECT LPAD(' ', level * 2, ' ') || TO_CHAR(position_nbr), descr
  FROM PS_POSITION_TBL
CONNECT BY PRIOR position_nbr = reports_to
START WITH reports_to IS NULL;

如果您不满意在单个列中显示级别 (LEVEL) 并且每个级别都需要一列，您可以使用基于 LEVEL 的 PIVOT 但是这会使排序有问题。

Answer 2

select    level1,level2,level3,level4,level5,level6,level7,level8,descr

from     (select        level as n,position_nbr as id,descr,position_nbr

          from          (         select position_nbr ,reports_to ,descr from PS_POSITION_TBL 
                        union all select 143          ,null       ,'CEO' from dual
                        )  t

          start with    reports_to is null

          connect by    reports_to = prior position_nbr
          ) 
          pivot (max(position_nbr) for n in (1 as level1,2 as level2,3 as level3,4 as level4,5 as level5,6 as level6,7 as level7,8 as level8))
;

或

select    decode (n,1,position_nbr) as level1
         ,decode (n,2,position_nbr) as level2
         ,decode (n,3,position_nbr) as level3
         ,decode (n,4,position_nbr) as level4
         ,decode (n,5,position_nbr) as level5
         ,decode (n,6,position_nbr) as level6
         ,decode (n,7,position_nbr) as level7
         ,decode (n,8,position_nbr) as level8
         ,descr

from     (select          level as n,position_nbr,descr

          from          (         select position_nbr ,reports_to ,descr from PS_POSITION_TBL 
                      union all select 143          ,null       ,'CEO' from dual
                      )  t

          start with    reports_to is null

          connect by    reports_to = prior position_nbr
          ) 
;

需要 SQL 查询平面结果集中的分层数据

Need SQL query for hierarchical data in a flat result set

sql

oracle

pivot

recursive-query