从派生的 table 中提取列并将它们汇总在一个 MySQL SELECT 语句中

Question

我需要从两个 table 中提取列数据，对数据进行运行计算，结果保存为别名，然后将这些结果汇总到其他别名中以显示在phptable。我试图通过在我的 SELECT 语句中创建派生的 table 来实现这一点，但它不起作用。我没有收到任何错误，但我的 table 仅显示 headers.

列

代码：

$sql = "SELECT x.company, x.stagestatus, x.shippeddate, SUM(x.totprice) as totalprice, SUM(x.sgtotquantity) as sgtotqty, SUM(x.sgtotalsqft) as sgtotsqft, SUM(x.avgsqftrev) as avgsqftrevenue, SUM(x.avgunitrev) as avgunitrevenue FROM (SELECT t1.company, t1.stagestatus, t1.shippeddate, t1.id, FORMAT(TRIM(LEADING '$' FROM t1.totalprice), 2) AS totprice, t2.invoiceid, SUM(t2.quantity) AS sgtotqauntity, FORMAT(SUM(t2.width * t2.height * t2.quantity ) /144, 2) AS sgtotalsqft, FORMAT((TRIM(LEADING '$' FROM t1.totalprice)/(SUM(t2.width * t2.height * t2.quantity ) /144)), 2) as avgsqftrev, FORMAT((TRIM(LEADING '$' FROM t1.totalprice) / SUM(t2.quantity)), 2) AS avgunitrev
  FROM invoices AS t1 INNER JOIN lineitems AS t2 ON t1.id = t2.invoiceid
  WHERE (t2.invoiceid = t1.id)
  GROUP BY t1.id) x
WHERE x.stagestatus='Complete'
GROUP BY x.company ASC";

这段代码会出错，但是当我单独使用较小的部分时，它工作正常。

EX:

$sql="SELECT invoices.id, invoices.orderdate, invoices.stagestatus, FORMAT(TRIM(LEADING '$' FROM invoices.totalprice), 2) AS totalprice, clients.company, lineitems.invoiceid, SUM(lineitems.quantity) AS sgtotqty, FORMAT(SUM(lineitems.width * lineitems.height * lineitems.quantity ) /144, 2) AS sgtotsqft, FORMAT((TRIM(LEADING '$' FROM invoices.totalprice)/(SUM(lineitems.width * lineitems.height * lineitems.quantity ) /144)), 2) as avgsqftrevenue, FORMAT((TRIM(LEADING '$' FROM invoices.totalprice) / SUM(lineitems.quantity)), 2) AS avgunitrevenue
FROM clients
INNER JOIN invoices ON clients.id = invoices.clientid
INNER JOIN lineitems ON invoices.id = lineitems.invoiceid
WHERE (lineitems.invoiceid = invoices.id) AND invoices.orderdate BETWEEN '".$revenuefrom."' AND '".$revenueto."' AND invoices.stagestatus IN (". implode(',', array_map(function($item) {return '"' . $item . '"'; }, $revenue_check)) .")
GROUP BY invoices.id DESC";

此代码运行良好，并按 invoices.id 对所有数据进行分组。但是项目需要调整，现在所有的东西都必须按invoices.company分组。当我简单地尝试按 invoices.company 而不是 invoices.id 分组时，我的 table 完成但每个公司行的值非常不准确，（sum() 不正确）。

PHP 构建 table 的代码：

$result = $conn->query($sql);


    echo "<table id='revenueReportA' align='center' class='report_DT'>
    <thead>
    <tr>

    <th>Customer</th>
    <th>Total Revenue</th>
    <th>Total SQ FT</th>
    <th>AVG Revenue Per SQ FT</th>
    <th>Total Number of Units</th>
    <th>AVG Revenue Per Unit</th>
    </tr>
    </head>";


 if ($result = $conn->query($sql)) {

   // fetch associative array 
  while ($row = $result->fetch_assoc()) {

  echo "<tbody>";
  echo "<tr>";
  echo "<td>" . $row['company'] . "</td>";
  echo "<td>" ."$". $row['totalprice'] . "</td>";
  echo "<td>" . $row['sgtotsqft'] ."&nbsp;&nbsp;". "ft<sup>2</sup>". "</td>";
  echo "<td>" ."$". $row['avgsqftrevenue'] . "</td>";
  echo "<td>" . $row['sgtotqty'] . "</td>";
  echo "<td>" ."$". $row['avgunitrevenue'] . "</td>";
  echo "</tr>";
  echo "</tbody>";
  } 

   echo "</table>";

echo "<BR>";

感谢所有帮助。

谢谢，

Answer 1

我有拼写错误和格式问题。通过格式化最终数据而不是在嵌入式 SELECT 语句中格式化，我的 table 数据是准确的。

成功代码：

$sql = "SELECT x.company, x.stagestatus, x.shippeddate, FORMAT(SUM(x.totprice), 2) as totalprice, FORMAT(SUM(x.sgtotquantity), 2) as sgtotqty, FORMAT(SUM(x.sgtotalsqft), 2) as sgtotsqft, FORMAT(SUM(x.avgsqftrev), 2) as avgsqftrevenue, FORMAT(SUM(x.avgunitrev), 2) as avgunitrevenue FROM (SELECT t1.company, t1.stagestatus, t1.shippeddate, t1.id, TRIM(LEADING '$' FROM t1.totalprice) AS totprice, t2.invoiceid, SUM(t2.quantity) AS sgtotquantity, SUM(t2.width * t2.height * t2.quantity ) /144 AS sgtotalsqft, (TRIM(LEADING '$' FROM t1.totalprice)/(SUM(t2.width * t2.height * t2.quantity ) /144)) as avgsqftrev, (TRIM(LEADING '$' FROM t1.totalprice) / SUM(t2.quantity)) AS avgunitrev
FROM invoices AS t1 INNER JOIN lineitems AS t2 ON t1.id = t2.invoiceid
WHERE (t2.invoiceid = t1.id)
GROUP BY t1.id) x
WHERE x.stagestatus='Complete'
GROUP BY x.company ASC";

谢谢！！！

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