SQL 服务器 Select 其中 stage/sequence 已丢失或顺序错误

SQL Server Select where stage/sequence has been missed or is out of sequence

我有一个 table,它有 families_iddatemetric_id

为每个 families_id 插入一条记录,将有一个 date & metric_id 1-10。

所以每个 families_id 应该有 10 条记录,这些记录被插入一个日期,每个记录应该相互接续。所以 metric_id 10 日期应该大于 metric_id 6 日期。

群发我怎么能select他们那里有

  1. 错过了 metric_id
  2. metric_id 6 的日期早于 metric_id 2
  3. 的日期

使用 row_number 为每个家庭分配 metric_id 和日期的序号,然后它们应该匹配 - 还有 metric_id、1,2,3,4...应该与其计算的 row_number() 相匹配,还有 1,2,3,4....

SELECT IQ.* FROM (SELECT families_id, [date], metric_id, 
        ROW_NUMBER() OVER (PARTITION BY families_id ORDER BY [date]) rn_date,
        ROW_NUMBER() OVER (PARTITION BY families_id ORDER BY metricid) rn_metric FROM YourTable) IQ 
    WHERE IQ.rn_date != IQ.rn_metric;

--should detect wrongly ordered metric_ids
SELECT IQ.* FROM (SELECT families_id, [date], metric_id, 
        ROW_NUMBER() OVER (PARTITION BY families_id ORDER BY [date]) rn_date,
        ROW_NUMBER() OVER (PARTITION BY families_id ORDER BY metricid) rn_metric FROM YourTable) IQ 
    WHERE IQ.metric_id != IQ.rn_metric;

另一种可能性 - 检测日期较早的 metricID 以获得更高的 ID

    SELECT y1.families_id, y1.metric_id FROM yourtable y1
                    WHERE 
                    EXISTS(SELECT 0 FROM yourtable y2 WHERE y1.families_id = y2.families_id 
                                                            AND
                                                            y2.date < y1.date 
                                                            AND
                                                            y2.metricid > y1.metricid)