如何将此 json 字符串转换为字典？

Question

执行以下代码后：

import json
a = '{"excludeTypes":"*.exe;~\$*.*"}'
json.loads(a)

我得到：

Traceback (most recent call last): File "", line 1, in File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/init.py", line 338, in loads return _default_decoder.decode(s) File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/decoder.py", line 365, in decode obj, end = self.raw_decode(s, idx=_w(s, 0).end()) File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/decoder.py", line 381, in raw_decode obj, end = self.scan_once(s, idx) ValueError: Expecting property name: line 1 column 2 (char 1)

那么如何将 'a' 转换为字典。 请注意，字符串已经在 'a' 中，我不能在它前面添加 'r'。理想情况下，字符串应该是 {"excludeTypes":"*.exe;~\\$*.*"}

此外，以下代码不起作用：

import json
a = '{"excludeTypes":"*.exe;~\$*.*"}'
b = repr(a)
json.loads(b)

Answer 1

import ast

d = ast.literal_eval(a)

Answer 2

通过转义转义字符“\”：

import json
a = '{"excludeTypes":"*.exe;~\$*.*"}'
a = a.replace("\","\\")
json.loads(a)