PL/SQL 将名称-值对转换为单行 table

Question

使用 PL/SQL，我如何转换 table 的名称-值对...

Name      Value
--------- -------
Firstname   Bob
Surname     Smith
Address1    101 High Street
City        London
Country     UK

...单行 table 像这样：

Firstname Surname Address1        City   Country
--------- ------- --------------- ------ -------
Bob       Smith   101 High Street London UK

实际上我需要的是将名称-值对转换为 SYS_REFCURSOR 作为上面的单行 table

完整的故事是：我收到的数据是像这样的单个字符串 (Firstname;Bob;Surname;SmithAddress1;101 High Street;City;London;Country;UK) 我需要的只是将其转换为 SYS_REFCURSOR

我从创建类型开始

TYPE order_type IS TABLE OF VARCHAR2(255) INDEX BY VARCHAR2(255);
neworder order_type;

到目前为止，我设法使用名称-值对做到了这一点

这是个好方法吗？

Answer 1

create table t1 (name varchar2(20), value varchar2(20));
insert into t1 values('Firstname','Bob');
insert into t1 values('Surname','Smith');
insert into t1 values('Address1','101 High Street');
insert into t1 values('City','London');
insert into t1 values('Country','UK');

select * from t1 pivot (max(value) for (name) in ('Firstname' as firstname, 'Surname' as surname, 'Address1' as address, 'City' as city, 'Country' as country));

这样SQL将列数据转换为一行。

如果您将数据作为具有固定顺序的分隔字符串获取，我将使用 instr('Firstname;Bob;Surname;Smith;Address1;101 High Street;City;London;Country;UK',';',1) 和 substring 函数的组合对其进行解析。

类似于：

declare
text varchar2(200) := 'Firstname;Bob;Surname;Smith;Address1;101 High Street;City;London;Country;UK';
firstname varchar2(40);
surname varchar2(40);
address varchar2(40);
city varchar2(40);
country varchar2(40);
begin
firstname := substr(text,instr(text,';',1) + 1,instr(text,';',2) - instr(text,';',1));
surname := substr(text,instr(text,';',3) + 1, instr(text,';',4) - instr(text,';',3));
....
end;

Answer 2

遇到了一个我不知道的有趣实用程序。 dbms_utility.comma_to_table。 http://mohsoracle.blogspot.com/2010/04/oracle-breaking-comma-separated-string.html

因此，如果您想将它用于 return 来自定界字符串的 sys ref 游标，可能类似于。

/* Formatted on 10/28/2016 9:42:52 AM (QP5 v5.256.13226.35510) */
CREATE OR REPLACE PROCEDURE myproc (v_cur OUT SYS_REFCURSOR)
IS
   lv_Str_List   VARCHAR2 (1000)
      := 'Firstname, Bob, Surname, Smith, Address, 101 High Street, City, London, Country, UK';
   lb_cnt        BINARY_INTEGER;
   la_Tab_Str    DBMS_UTILITY.UNCL_ARRAY;
BEGIN
   lv_Str_List := '"' || REPLACE (lv_Str_List, ',', '","') || '"';
   -- parse the string into comma separated table
   DBMS_UTILITY.COMMA_TO_TABLE (lv_Str_List, lb_cnt, la_Tab_Str);

   FOR i IN 1 .. la_Tab_Str.COUNT
   LOOP
      -- display substring
      DBMS_OUTPUT.PUT_LINE (TRIM (la_Tab_Str (i)));
   END LOOP;

   OPEN v_cur FOR
      SELECT *
        FROM (SELECT REPLACE (TRIM (la_Tab_Str (2)), '"', '') AS Firstname,
                     REPLACE (TRIM (la_Tab_Str (4)), '"', '') AS Surname,
                     REPLACE (TRIM (la_Tab_Str (6)), '"', '') AS Address,
                     REPLACE (TRIM (la_Tab_Str (8)), '"', '') AS City,
                     REPLACE (TRIM (la_Tab_Str (10)), '"', '') AS Country
                FROM DUAL) t;
END;

我在字符串中进行了硬编码，但它可以作为变量出现，然后用逗号替换分号。

当我运行下面在toad中测试一下。

DECLARE 
  V_CUR SYS_REFCURSOR;

BEGIN 
  V_CUR := NULL;

  MYPROC ( V_CUR );
  :to_grid := V_CUR;
  COMMIT; 
END;

我得到了

FIRSTNAME SURNAME  ADDRESS           CITY     COUNTRY
Bob       Smith    101 High Street   London   UK

PL/SQL 将名称-值对转换为单行 table

PL/SQL converts name-value pairs to single row table

database

oracle

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