将值传递给另一个视图控制器并设置为等于输出时，我不断收到解包错误？ (Swift 3.0)

Question

当我尝试将我的函数 return 值设置为标签输出时，我不断收到此错误。

import UIKit

class finalData: UIViewController {

var userNum: Int!
var computerNum: Int!

@IBOutlet var output: UILabel!

override func viewDidLoad() {
    super.viewDidLoad()

    self.output.text = chooseWinner(userNum: userNum, computerNum: computerNum)
    // Do any additional setup after loading the view.


}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}

func chooseWinner(userNum : Int, computerNum : Int) -> String {
    if userNum == computerNum {
        return "There is a tie"
    }else if userNum == 1 && computerNum == 2{
        return "You lost!"
    }else if userNum == 1 && computerNum == 3{
        return "You won!"
    }else if userNum == 2 && computerNum == 1{
        return "You won!"
    }
    else if userNum == 2 && computerNum == 3{
        return "You lost!"
    }else if userNum == 3 && computerNum == 1{
        return "You lost!"
    }
    else if userNum == 3 && computerNum == 2{
        return "You won!"
    }else{
        return "value"
    }
}

func findPlayerImage (firstImage: Int) -> UIImage{
    if userNum == 1{
        return #imageLiteral(resourceName: "black")
    }else if userNum == 2{
        return #imageLiteral(resourceName: "black")
    }else{
        return #imageLiteral(resourceName: "black")
    }
}
func findCompImage (secondImage: Int) -> UIImage{
    if computerNum == 1{
        return #imageLiteral(resourceName: "black")
    }else if computerNum == 2{
        return #imageLiteral(resourceName: "black")
    }else{
        return #imageLiteral(resourceName: "black")
    }
}

/*
// MARK: - Navigation

// In a storyboard-based application, you will often want to do a little preparation before navigation
override func prepare(for segue: UIStoryboardSegue, sender: Any?) {
    // Get the new view controller using segue.destinationViewController.
    // Pass the selected object to the new view controller.
}
*/

}

我正在尝试将数字传递给此视图控制器，然后将函数调用到 return 字符串（我正在制作剪刀石头布）。但是，当我设置输出 = 函数时，它给了我一个解包错误。

Answer 1

我确保我的连接良好。

然后我把这个值传给另一个storyboard，把output的默认值设置为"value"。当我将字符串传递到输出时，它发生了变化。

也谢谢楼上的各位。 ^

将值传递给另一个视图控制器并设置为等于输出时，我不断收到解包错误？ (Swift 3.0)

I keep getting an unwrapping error when passing value to another view controller and set equal to output? (Swift 3.0)

null

func

swift

unwrap