java 中的拆分矩阵

Question

我找到了类似的问题，但不是我想要的。

我需要将一个 1024x1024 的矩阵分成 4 个相等的部分，但我必须将每个部分的开头和结尾都花在另一个 class 线程中。我考虑过使用两个循环，但我不知道如何正确更改变量的值，因为它超过了最大值。

代码：

private static final int MAX_MATRIX = 1024;
private static final int NUM_THREADS = 4;
int start_row = 0, end_row = 0, start_column = 0, end_column = 0;
for (int i = 0; i < NUM_THREADS/2; i++){
 end_row = start_row + (MAX_MATRIX/2);      
 for (int j = 0; j < (NUM_THREADS/2); j++){
    end_column = start_column + (MAX_MATRIX/2);
    myTask[i] = new TaskAnalyze(start_row, end_row, start_column, end_column, int_radom);
    myThreads[i] = new Thread(myTask[i],"TASK " + i);
 }      
 start_column += MAX_MATRIX/2;      
 start_row += MAX_MATRIX/2; 
}

int_random是矩阵。

应该有的是：

myTask[0] = new TaskAnalyze(0, 512, 0, 512, int_radom);

myTask[1] = new TaskAnalyze(0, 512, 512, 1024, int_radom);

myTask[2] = new TaskAnalyze(512, 1024, 0, 512, int_radom);

myTask[3] = new TaskAnalyze(512, 1024, 512, 1024, int_radom);

有什么建议吗？

Answer 1

试试这个：

int MAX_MATRIX = 1024;
int NUM_THREADS = 4;
int start_row = 0, end_row = 0, start_column = 0, end_column = 0;
for (int i = 0; i < NUM_THREADS/2; i++){
    start_row = i*MAX_MATRIX/2;
    end_row = start_row + MAX_MATRIX/2;
    for (int j = 0; j < NUM_THREADS/2; j++){
        start_column = j*MAX_MATRIX/2;
        end_column = start_column + MAX_MATRIX/2;
        System.out.println(start_row + "," + end_row + "," + start_column + "," + end_column);
    }
}

应该会得到以下输出：

0,512,0,512
0,512,512,1024
512,1024,0,512
512,1024,512,1024

然后您可以将 System.out.println 行替换为您的行：

myTask[i] = new TaskAnalyze(start_row, end_row, start_column, end_column, int_radom);
myThreads[i] = new Thread(myTask[i],"TASK " + i);

java 中的拆分矩阵

Split matrix in java

java

multithreading

loops

matrix

division