SKPhysicsBody "Extra argument 'size' in call"

Question

我想要实现的是使对象（物理体）的形状与纹理完全一样，以便将来只能单击纹理（而不是透明层）。

    let fireLayer = SKSpriteNode(imageNamed: fireImage)
    fireLayer.anchorPoint = CGPointMake(1, 0)
    fireLayer.position = CGPointMake(size.width, 0)
    fireLayer.zPosition = Layer.Z4st

    var firedown = SKAction.moveToY(-200, duration: 0)
    var fireup1 = SKAction.moveToY(10, duration: 1.2)
    var fireup2 = SKAction.moveToY(0, duration: 0.2)

在这里，我正在尝试为 "cut out" 节点所需的对象创建实体。

    fireLayer.physicsBody = SKPhysicsBody(texture: fireLayer, size: fireLayer.texture!.size())

现在，这里我得到一个错误"Extra argument 'size' in call"...虽然SKPhysicalBody有两个参数：texture和size。

    fireLayer.name = "fireNode"

    fireLayer.runAction(SKAction.sequence([firedown, wait1, fireup1, fireup2]))

    addChild(fireLayer)

我做错了什么？提前致谢！

Answer 1

此错误具有误导性。你的问题其实是第一个参数texture: fireLayer。您需要设置 SKTexture 而不是 SKSpriteNode。

您还应该更改初始化 SKSpriteNode 的方式并添加 SKTexture：

let fireLayerTexture = SKTexture(imageNamed: fireImage)

比：

let fireLayer = SKSpriteNode(texture: fireLayerTexture)

完成后，您可以像这样初始化 SKPhysicsBody：

fireLayer.physicsBody = SKPhysicsBody(texture: fireLayerTexture, size: fireLayer.texture!.size())

SKPhysicsBody "Extra argument 'size' in call"

SKPhysicsBody "Extra argument 'size' in call"

size

skphysicsbody

swift