过滤器选项中的逻辑运算符
Logical operators in the filter option
如何在过滤器中使用两个参数?
var source3 = Game.spawns.Spawn1.pos.findClosest(Game.SOURCES_ACTIVE, {
filter: function(object) {
return object.id != source1 && source2;
}
}).id;
因为我的过滤器只考虑参数 'source1'...
只要确保你在第二部分也添加了比较object.id != source2
var source3 = Game.spawns.Spawn1.pos.findClosest(Game.SOURCES_ACTIVE, {
filter: function(object) {
return object.id != source1 && object.id != source2;
}
}).id;
如何在过滤器中使用两个参数?
var source3 = Game.spawns.Spawn1.pos.findClosest(Game.SOURCES_ACTIVE, {
filter: function(object) {
return object.id != source1 && source2;
}
}).id;
因为我的过滤器只考虑参数 'source1'...
只要确保你在第二部分也添加了比较object.id != source2
var source3 = Game.spawns.Spawn1.pos.findClosest(Game.SOURCES_ACTIVE, {
filter: function(object) {
return object.id != source1 && object.id != source2;
}
}).id;