Leaper 如果表达错误

Question

import java.util.*;

public class LeapYear {

    public static void main (String args[]) {

        Scanner scan = new Scanner(System.in);
        int userInput = scan.nextInt();
        boolean leapYearisTrue = false;

        while ( userInput != 0 ) {
            if (userInput % 4 == 0) {
                if ( (userInput % 100 == 0) && (userInput % 400 != 0) ) {
                    leapYearisTrue = false;
                    System.out.println (leapYearisTrue);
                }
                else {
                    leapYearisTrue = true;
                    System.out.println (leapYearisTrue);
                }
                userInput = scan.nextInt();
            }
        }
    }
}

每当我输入一个闰年的值时，程序都会顺利运行并执行预期的操作：

2000
true
1960
true
400
true

但是每当我输入一个非闰年时，它不会打印错误，也不会再打印一个数字是闰年：

403
400
2000 ( this is a leap year , yet it doesn't print true)
2004

Answer 1

您需要在 if (userInput % 4 == 0) 条件中添加一个 else 条件。

Answer 2

试试这个：

import java.util.*;

public class LeapYear {

    public static void main(String args[]) {

        System.out.println("Enter the year: \n");    
        Scanner scan = new Scanner(System.in);
        int userInput = scan.nextInt();
        boolean leapYearisTrue = false;

        while (userInput != 0) {
            if (userInput % 4 == 0) {
                if (userInput % 100 == 0) {
                    if (userInput % 400 != 0) {
                        leapYearisTrue = true;
                        System.out.println(leapYearisTrue);
                    }
                } else {
                    leapYearisTrue = true;
                    System.out.println(leapYearisTrue);
                }
                userInput = scan.nextInt();
            }
        }
    }
}

Leaper 如果表达错误

Leaper if expression is faulty

java

leap-year