bash

Question

在 Kubuntu 15.10 上

echo $BASH_VERSION
4.3.42(1)-release

我试试

reps=1
threads={1}{10..60..10}

for((r=0;r<$reps;r++))
do
    tCount=0
    for t in $threads
    do
        echo "t=$t, tCount=${tCount}"
        #do something funny with it
        ((tCount++))
    done
done

它产生一行

t={1}{10..60..10}, tCount=0

我如何让它工作？

编辑

我希望

t=1, tCount=0
t=10, tCount=1
t=20, tCount=2
t=30, tCount=3
t=40, tCount=4
t=50, tCount=5
t=60, tCount=6

更新

请注意 threads=({1}{10..60..10})

然后是for t in ${threads[@]}

将在 10..60..10 范围前加上字符串 {1}

（即 {1}10,{1}20,..,{1}60）

Answer 1

{1} 表达式只是一个字符串，因为它不符合大括号扩展语法：

A sequence expression takes the form {X..Y[..INCR]}, where X and Y are either integers or single characters, and INCR, an optional increment, is an integer.

大括号展开在变量展开之前进行，所以不能仅仅通过引用一个变量来展开大括号:

The order of expansions is: brace expansion; tilde expansion, parameter and variable expansion, arithmetic expansion, and command substitution (done in a left-to-right fashion); word splitting; and filename expansion.

是直接写大括号展开，还是用eval（通常不推荐）。

示例：

tCount=0
for t in {1,{10..60..10}}; do
  echo "t=$t tCount=$tCount"
  (( tCount++ ))
done

bash - 括号扩展没有扩展？

bash - brace expansion not expanding?

range

brace-expansion