显示包含 VARRAY 列的记录
display a record which contains a VARRAY column
我有一个 returns 记录的功能。
记录的列之一是 VARRAY。
有人可以提示我如何显示记录吗? (我的问题与 VARRAY 列有关。
create or replace TYPE phone_list_typ AS VARRAY(5) OF VARCHAR2(25);
CREATE TABLE "CUSTOMERS"
("CUSTOMER_ID" NUMBER(6,0),
"CUST_FIRST_NAME" VARCHAR2(20 BYTE)
"PHONE_NUMBERS" "OE"."PHONE_LIST_TYP" ,
"CREDIT_LIMIT" NUMBER(9,2),
"CUST_EMAIL" VARCHAR2(40 BYTE));
TYPE r_cust_det IS RECORD( CUSTOMER_ID customers.CUSTOMER_ID%TYPE
, CUST_FIRST_NAME customers.CUST_FIRST_NAME%TYPE
, PHONE_NUMBERS customers.PHONE_NUMBERS%TYPE
, CREDIT_LIMIT customers.CREDIT_LIMIT%TYPE
, CUST_EMAIL customers.CUST_EMAIL%TYPE);
CREATE OR REPLACE FUNCTION show_customer_details (n_customer_id customers.customer_id%TYPE) RETURN r_cust_det
IS
v_return r_cust_det;
BEGIN
SELECT CUSTOMER_ID
, CUST_FIRST_NAME
, PHONE_NUMBERS
, CREDIT_LIMIT
, CUST_EMAIL
INTO v_return
FROM CUSTOMERS
WHERE CUSTOMER_ID = n_customer_id;
RETURN v_return;
END show_customer_details;
这可能取决于您希望它的外观和显示介质(文本文件、交互式网页等),但一种方法可能是将 phone 数字列为逗号分隔列表。
select customer_id, cust_first_name, credit_limit, cust_email
, listagg(p.column_value,', ') within group (order by p.column_value) as phone_numbers
from customers c cross join table(c.phone_numbers) p
group by customer_id, cust_first_name, credit_limit, cust_email
order by customer_id;
不过,我不确定您对 show_customer_details
函数有什么期望。
(顺便说一句,除非绝对必要,否则将标识符括在双引号中不是一个好主意。)
CREATE OR REPLACE FUNCTION show_customer_details (n_customer_id customers.customer_id%TYPE) RETURN t_cust_det PIPELINED
IS
v_return t_cust_det;
BEGIN
SELECT t1.CUSTOMER_ID
, t1.CUST_FIRST_NAME
, t2.*
, t1.CREDIT_LIMIT
, t1.CUST_EMAIL
BULK COLLECT INTO v_return
FROM CUSTOMERS t1, table(t1.phone_numbers) t2
WHERE t1.CUSTOMER_ID = n_customer_id
AND column_value is not null;
FOR i IN 1 .. v_return.count
LOOP
PIPE ROW (v_return(i));
END LOOP;
END show_customer_details;
函数调用是:
select * from table(SHOW_DETAILS.SHOW_CUSTOMER_DETAILS(101));
我找到的另一个解决方案,不使用 PIPELINED 是:
定义对象类型
create or replace type customers_typ
is object
( CUSTOMER_ID number(6)
, CUST_FIRST_NAME varchar2(20)
, PHONE_NUMBERS varchar2(25) --phone_list_typ
, CREDIT_LIMIT number(9, 2)
, CUST_EMAIL varchar2(40)
);
定义一个新类型,table 以前定义的对象。
create or replace type t_customers_typ is table of customers_typ;
函数变为
CREATE OR REPLACE FUNCTION show_customer_details (n_customer_id customers.customer_id%TYPE) RETURN t_customers_typ
IS
v_return t_customers_typ;
BEGIN
SELECT customers_typ(t1.CUSTOMER_ID
, t1.CUST_FIRST_NAME
, t2.column_value
, t1.CREDIT_LIMIT
, t1.CUST_EMAIL)
BULK COLLECT INTO v_return
FROM CUSTOMERS t1, table(t1.phone_numbers) t2
WHERE t1.CUSTOMER_ID = n_customer_id
AND t2.column_value is not null;
return v_return;
END show_customer_details;
函数调用方式相同:
select * from table(SHOW_DETAILS.SHOW_CUSTOMER_DETAILS(101));
我有一个 returns 记录的功能。 记录的列之一是 VARRAY。 有人可以提示我如何显示记录吗? (我的问题与 VARRAY 列有关。
create or replace TYPE phone_list_typ AS VARRAY(5) OF VARCHAR2(25);
CREATE TABLE "CUSTOMERS"
("CUSTOMER_ID" NUMBER(6,0),
"CUST_FIRST_NAME" VARCHAR2(20 BYTE)
"PHONE_NUMBERS" "OE"."PHONE_LIST_TYP" ,
"CREDIT_LIMIT" NUMBER(9,2),
"CUST_EMAIL" VARCHAR2(40 BYTE));
TYPE r_cust_det IS RECORD( CUSTOMER_ID customers.CUSTOMER_ID%TYPE
, CUST_FIRST_NAME customers.CUST_FIRST_NAME%TYPE
, PHONE_NUMBERS customers.PHONE_NUMBERS%TYPE
, CREDIT_LIMIT customers.CREDIT_LIMIT%TYPE
, CUST_EMAIL customers.CUST_EMAIL%TYPE);
CREATE OR REPLACE FUNCTION show_customer_details (n_customer_id customers.customer_id%TYPE) RETURN r_cust_det
IS
v_return r_cust_det;
BEGIN
SELECT CUSTOMER_ID
, CUST_FIRST_NAME
, PHONE_NUMBERS
, CREDIT_LIMIT
, CUST_EMAIL
INTO v_return
FROM CUSTOMERS
WHERE CUSTOMER_ID = n_customer_id;
RETURN v_return;
END show_customer_details;
这可能取决于您希望它的外观和显示介质(文本文件、交互式网页等),但一种方法可能是将 phone 数字列为逗号分隔列表。
select customer_id, cust_first_name, credit_limit, cust_email
, listagg(p.column_value,', ') within group (order by p.column_value) as phone_numbers
from customers c cross join table(c.phone_numbers) p
group by customer_id, cust_first_name, credit_limit, cust_email
order by customer_id;
不过,我不确定您对 show_customer_details
函数有什么期望。
(顺便说一句,除非绝对必要,否则将标识符括在双引号中不是一个好主意。)
CREATE OR REPLACE FUNCTION show_customer_details (n_customer_id customers.customer_id%TYPE) RETURN t_cust_det PIPELINED
IS
v_return t_cust_det;
BEGIN
SELECT t1.CUSTOMER_ID
, t1.CUST_FIRST_NAME
, t2.*
, t1.CREDIT_LIMIT
, t1.CUST_EMAIL
BULK COLLECT INTO v_return
FROM CUSTOMERS t1, table(t1.phone_numbers) t2
WHERE t1.CUSTOMER_ID = n_customer_id
AND column_value is not null;
FOR i IN 1 .. v_return.count
LOOP
PIPE ROW (v_return(i));
END LOOP;
END show_customer_details;
函数调用是:
select * from table(SHOW_DETAILS.SHOW_CUSTOMER_DETAILS(101));
我找到的另一个解决方案,不使用 PIPELINED 是:
定义对象类型
create or replace type customers_typ
is object
( CUSTOMER_ID number(6)
, CUST_FIRST_NAME varchar2(20)
, PHONE_NUMBERS varchar2(25) --phone_list_typ
, CREDIT_LIMIT number(9, 2)
, CUST_EMAIL varchar2(40)
);
定义一个新类型,table 以前定义的对象。
create or replace type t_customers_typ is table of customers_typ;
函数变为
CREATE OR REPLACE FUNCTION show_customer_details (n_customer_id customers.customer_id%TYPE) RETURN t_customers_typ
IS
v_return t_customers_typ;
BEGIN
SELECT customers_typ(t1.CUSTOMER_ID
, t1.CUST_FIRST_NAME
, t2.column_value
, t1.CREDIT_LIMIT
, t1.CUST_EMAIL)
BULK COLLECT INTO v_return
FROM CUSTOMERS t1, table(t1.phone_numbers) t2
WHERE t1.CUSTOMER_ID = n_customer_id
AND t2.column_value is not null;
return v_return;
END show_customer_details;
函数调用方式相同:
select * from table(SHOW_DETAILS.SHOW_CUSTOMER_DETAILS(101));