不确定如何在我的 android 秒表上表达我的重置操作
Not sure how to word my Reset action on my android stopwatch
我尝试了多种方法来解决我的问题,但我对编码还很陌生,所以我需要有关如何正确 'Word' 重置秒表的秒表动作的帮助。它需要做的就是以某种方式将当前值重置回 00:00:00,就像计时器启动之前一样,但我不确定该怎么做...这是 00:00:00 的部分=31=] 我正在努力解决的问题:
resetButton = (Button) findViewById(R.id.reset);
return timeInMillies = startTime;
resetButton.setOnClickListener(SystemClock.setCurrentTimeMillis(timeInMillies = 00:00:00))
long timeInMillies = 0L;
long timeSwap = 0L;
long finalTime = 0L;
但是,其他一切都很好,并且很有魅力。如果对您有所帮助,请阅读完整的XML:
package com.jackson.eason.stopwatch;
import android.app.Activity;
import android.os.Bundle;
import android.os.Handler;
import android.os.SystemClock;
import android.view.View;
import android.widget.Button;
import android.widget.TextView;
public class MainActivity extends Activity {
/** Called when the activity is first created. */
private Button startButton;
private Button pauseButton;
private Button resetButton;
private long startTime = 0L;
private Handler myHandler = new Handler();
long timeInMillies = 0L;
long timeSwap = 0L;
long finalTime = 0L;
private TextView textTimer;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
textTimer = (TextView) findViewById(R.id.textTimer);
startButton = (Button) findViewById(R.id.start);
startButton.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
startTime = SystemClock.uptimeMillis();
myHandler.postDelayed(updateTimerMethod, 0);
}
});
pauseButton = (Button) findViewById(R.id.stop);
pauseButton.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
timeSwap += timeInMillies;
myHandler.removeCallbacks(updateTimerMethod);
}
});
resetButton = (Button) findViewById(R.id.reset);
return timeInMillies = startTime;
resetButton.setOnClickListener(SystemClock.setCurrentTimeMillis(timeInMillies = 00:00:00))
long timeInMillies = 0L;
long timeSwap = 0L;
long finalTime = 0L;
}
private Runnable updateTimerMethod = new Runnable() {
public void run() {
timeInMillies = SystemClock.uptimeMillis() - startTime;
finalTime = timeSwap + timeInMillies;
int seconds = (int) (finalTime / 1000);
int minutes = seconds / 60;
seconds = seconds % 60;
int milliseconds = (int) (finalTime % 1000);
textTimer.setText("" + minutes + ":"
+ String.format("%02d", seconds) + ":"
+ String.format("%03d", milliseconds));
myHandler.postDelayed(this, 0);
}
};
}
非常感谢任何帮助!
对于重置按钮,您需要更改两处:
1) 文本框。
2) 保持startTime和timeSwap的变量。
但您不想更改应用程序的阶段,我将通过以下方式进行更改:
resetButton.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
textTimer.setText("" + 00 + ":"
+ String.format("%02d", 00) + ":"
+ String.format("%03d", 00));
startTime = SystemClock.uptimeMillis();
timeSwap=0;
}
});
我尝试了多种方法来解决我的问题,但我对编码还很陌生,所以我需要有关如何正确 'Word' 重置秒表的秒表动作的帮助。它需要做的就是以某种方式将当前值重置回 00:00:00,就像计时器启动之前一样,但我不确定该怎么做...这是 00:00:00 的部分=31=] 我正在努力解决的问题:
resetButton = (Button) findViewById(R.id.reset);
return timeInMillies = startTime;
resetButton.setOnClickListener(SystemClock.setCurrentTimeMillis(timeInMillies = 00:00:00))
long timeInMillies = 0L;
long timeSwap = 0L;
long finalTime = 0L;
package com.jackson.eason.stopwatch;
import android.app.Activity;
import android.os.Bundle;
import android.os.Handler;
import android.os.SystemClock;
import android.view.View;
import android.widget.Button;
import android.widget.TextView;
public class MainActivity extends Activity {
/** Called when the activity is first created. */
private Button startButton;
private Button pauseButton;
private Button resetButton;
private long startTime = 0L;
private Handler myHandler = new Handler();
long timeInMillies = 0L;
long timeSwap = 0L;
long finalTime = 0L;
private TextView textTimer;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
textTimer = (TextView) findViewById(R.id.textTimer);
startButton = (Button) findViewById(R.id.start);
startButton.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
startTime = SystemClock.uptimeMillis();
myHandler.postDelayed(updateTimerMethod, 0);
}
});
pauseButton = (Button) findViewById(R.id.stop);
pauseButton.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
timeSwap += timeInMillies;
myHandler.removeCallbacks(updateTimerMethod);
}
});
resetButton = (Button) findViewById(R.id.reset);
return timeInMillies = startTime;
resetButton.setOnClickListener(SystemClock.setCurrentTimeMillis(timeInMillies = 00:00:00))
long timeInMillies = 0L;
long timeSwap = 0L;
long finalTime = 0L;
}
private Runnable updateTimerMethod = new Runnable() {
public void run() {
timeInMillies = SystemClock.uptimeMillis() - startTime;
finalTime = timeSwap + timeInMillies;
int seconds = (int) (finalTime / 1000);
int minutes = seconds / 60;
seconds = seconds % 60;
int milliseconds = (int) (finalTime % 1000);
textTimer.setText("" + minutes + ":"
+ String.format("%02d", seconds) + ":"
+ String.format("%03d", milliseconds));
myHandler.postDelayed(this, 0);
}
};
}
非常感谢任何帮助!
对于重置按钮,您需要更改两处:
1) 文本框。
2) 保持startTime和timeSwap的变量。
但您不想更改应用程序的阶段,我将通过以下方式进行更改:
resetButton.setOnClickListener(new View.OnClickListener() {
public void onClick(View view) {
textTimer.setText("" + 00 + ":"
+ String.format("%02d", 00) + ":"
+ String.format("%03d", 00));
startTime = SystemClock.uptimeMillis();
timeSwap=0;
}
});