遍历 0 到 100（含）之间的所有 3 的倍数，并打印能被 2 整除的那些

Question

我目前拥有的：

num = range(0, 101, 3)
list = []

if num % 3 == 0:
    list.append

print(list)

Answer 1

lst = []   # don't use Python inbuilt names for variables

for num in range(0,101,3):
    if num % 2 == 0:              # you already go through the numbers in steps of 3
        lst.append(num)

print(lst)

Answer 2

我想这就是你想要做的：

print("\n".join(str(i) for i in range(0, 101, 3) if i % 2 == 0))

或

print([i for i in range(0, 101, 3) if i % 2 == 0])

我在这里使用列表理解。

print(list(range(0, 101, 6)))

但是做同样的事情。

遍历 0 到 100（含）之间的所有 3 的倍数，并打印能被 2 整除的那些

Go over all multiples of 3 between 0 and 100 (inclusive), and print the ones that are divisible by 2

python

list

modulus