Bash 带有多个条件的 if 语句脚本

Bash script if statement with multiple conditions

我正在尝试为 vagrant puppet dev env 创建一个简单的 bash shell 脚本供应器,它检查 /tmp/puppet-modules-up-to-date 是否存在并且是在特定时间范围内创建的,14 天准确地说。我正在努力使用这个简单的脚本来取得进展。任何帮助表示赞赏。

#!/bin/bash

if [[ ! -f /tmp/.puppet-modules-up-to-date ]] && [[ ! (find /tmp/.puppet-modules-up-to-date -mtime -14 | grep puppet) ]]; then

    puppet_dir=/etc/puppet

    echo 'Copying Puppetfile into place'
    cp /vagrant/puppet/Puppetfile $puppet_dir

    cd $puppet_dir

    echo 'Installing puppet modules into place'
    librarian-puppet install

    echo 'Updating previously installed puppet modules'
    librarian-puppet update 

    touch /tmp/.puppet-modules-up-to-date
fi

只是给我以下错误:

==> default: /tmp/vagrant-shell: line 3: conditional binary operator expected
==> default: /tmp/vagrant-shell: line 3: expected `)'
==> default: /tmp/vagrant-shell: line 3: syntax error near `/tmp/.puppet-modules-up-to-date'
==> default: /tmp/vagrant-shell: line 3: `if [[ ! -f /tmp/.puppet-modules-up-to-date ]] && [[ ! (find /tmp/.puppet-modules-up-to-date -mtime -14 | grep puppet) ]]; then'

问题似乎出在这里:

[[ ! (find /tmp/.puppet-modules-up-to-date -mtime -14 | grep puppet) ]];

因为这并不是真正捕获 find/grep 的输出,您可以使用 $(find...) 命令执行此操作。

但是您可以使用 grep -q:

更好地处理这种情况
find /tmp/.puppet-modules-up-to-date -mtime -14 | grep -vq puppet