graphene-django - 如何过滤?
graphene-django - How to filter?
我使用 graphen-django 构建 GraphQL API。
我已成功创建此 API,但我无法传递参数来过滤我的回复。
这是我的models.py:
from django.db import models
class Application(models.Model):
name = models.CharField("nom", unique=True, max_length=255)
sonarQube_URL = models.CharField("Url SonarQube", max_length=255, blank=True, null=True)
def __unicode__(self):
return self.name
这是我的schema.py:
进口石墨烯
从 graphene_django 导入 DjangoObjectType
从模型导入应用程序
class Applications(DjangoObjectType):
class Meta:
model = Application
class Query(graphene.ObjectType):
applications = graphene.List(Applications)
@graphene.resolve_only_args
def resolve_applications(self):
return Application.objects.all()
schema = graphene.Schema(query=Query)
我的urls.py:
urlpatterns = [
url(r'^', include(router.urls)),
url(r'^admin/', admin.site.urls),
url(r'^api-auth/', include('rest_framework.urls', namespace='rest_framework')),
url(r'^api-token-auth/', authviews.obtain_auth_token),
url(r'^graphql', GraphQLView.as_view(graphiql=True)),
]
如你所见,我也有一个 REST API。
我的settings.py包含这个:
GRAPHENE = {
'SCHEMA': 'tibco.schema.schema'
}
我遵循这个:https://github.com/graphql-python/graphene-django
当我发送这个请求时:
{
applications {
name
}
}
我收到了这样的回复:
{
"data": {
"applications": [
{
"name": "foo"
},
{
"name": "bar"
}
]
}
}
所以,成功了!
但是当我尝试传递这样的参数时:
{
applications(name: "foo") {
name
id
}
}
我有这样的回复:
{
"errors": [
{
"message": "Unknown argument \"name\" on field \"applications\" of type \"Query\".",
"locations": [
{
"column": 16,
"line": 2
}
]
}
]
}
我错过了什么?或者我做错了什么?
我找到了解决方案,感谢:https://docs.graphene-python.org/projects/django/en/latest/
这是我的答案。我已经编辑了我的 schema.py:
import graphene
from graphene import relay, AbstractType, ObjectType
from graphene_django import DjangoObjectType
from graphene_django.filter import DjangoFilterConnectionField
from models import Application
class ApplicationNode(DjangoObjectType):
class Meta:
model = Application
filter_fields = ['name', 'sonarQube_URL']
interfaces = (relay.Node, )
class Query(ObjectType):
application = relay.Node.Field(ApplicationNode)
all_applications = DjangoFilterConnectionField(ApplicationNode)
schema = graphene.Schema(query=Query)
然后,它缺少一个包:django-filter (https://github.com/carltongibson/django-filter/tree/master)。
Django-filter 由 DjangoFilterConnectionField 使用。
现在我可以做到了:
query {
allApplications(name: "Foo") {
edges {
node {
name
}
}
}
}
响应将是:
{
"data": {
"allApplications": {
"edges": [
{
"node": {
"name": "Foo"
}
}
]
}
}
}
如果您是我的情况并且不想使用 Relay,您也可以使用 Django orm 过滤直接在解析器中处理过滤。此处示例:Filter graphql query in django
对 Adrien Answer 的补充很少。如果您想在过滤包含和完全匹配时执行不同的操作,请编辑您的 schema.py
class ApplicationNode(DjangoObjectType):
class Meta:
model = Application
# Provide more complex lookup types
filter_fields = {
'name': ['exact', 'icontains', 'istartswith']
}
interfaces = (relay.Node, )
你可以这样写查询
query {
allApplications(name_Icontains: "test") {
edges {
node {
id,
name
}
}
}
}
我使用 graphen-django 构建 GraphQL API。 我已成功创建此 API,但我无法传递参数来过滤我的回复。
这是我的models.py:
from django.db import models
class Application(models.Model):
name = models.CharField("nom", unique=True, max_length=255)
sonarQube_URL = models.CharField("Url SonarQube", max_length=255, blank=True, null=True)
def __unicode__(self):
return self.name
这是我的schema.py: 进口石墨烯 从 graphene_django 导入 DjangoObjectType 从模型导入应用程序
class Applications(DjangoObjectType):
class Meta:
model = Application
class Query(graphene.ObjectType):
applications = graphene.List(Applications)
@graphene.resolve_only_args
def resolve_applications(self):
return Application.objects.all()
schema = graphene.Schema(query=Query)
我的urls.py:
urlpatterns = [
url(r'^', include(router.urls)),
url(r'^admin/', admin.site.urls),
url(r'^api-auth/', include('rest_framework.urls', namespace='rest_framework')),
url(r'^api-token-auth/', authviews.obtain_auth_token),
url(r'^graphql', GraphQLView.as_view(graphiql=True)),
]
如你所见,我也有一个 REST API。
我的settings.py包含这个:
GRAPHENE = {
'SCHEMA': 'tibco.schema.schema'
}
我遵循这个:https://github.com/graphql-python/graphene-django
当我发送这个请求时:
{
applications {
name
}
}
我收到了这样的回复:
{
"data": {
"applications": [
{
"name": "foo"
},
{
"name": "bar"
}
]
}
}
所以,成功了!
但是当我尝试传递这样的参数时:
{
applications(name: "foo") {
name
id
}
}
我有这样的回复:
{
"errors": [
{
"message": "Unknown argument \"name\" on field \"applications\" of type \"Query\".",
"locations": [
{
"column": 16,
"line": 2
}
]
}
]
}
我错过了什么?或者我做错了什么?
我找到了解决方案,感谢:https://docs.graphene-python.org/projects/django/en/latest/
这是我的答案。我已经编辑了我的 schema.py:
import graphene
from graphene import relay, AbstractType, ObjectType
from graphene_django import DjangoObjectType
from graphene_django.filter import DjangoFilterConnectionField
from models import Application
class ApplicationNode(DjangoObjectType):
class Meta:
model = Application
filter_fields = ['name', 'sonarQube_URL']
interfaces = (relay.Node, )
class Query(ObjectType):
application = relay.Node.Field(ApplicationNode)
all_applications = DjangoFilterConnectionField(ApplicationNode)
schema = graphene.Schema(query=Query)
然后,它缺少一个包:django-filter (https://github.com/carltongibson/django-filter/tree/master)。 Django-filter 由 DjangoFilterConnectionField 使用。
现在我可以做到了:
query {
allApplications(name: "Foo") {
edges {
node {
name
}
}
}
}
响应将是:
{
"data": {
"allApplications": {
"edges": [
{
"node": {
"name": "Foo"
}
}
]
}
}
}
如果您是我的情况并且不想使用 Relay,您也可以使用 Django orm 过滤直接在解析器中处理过滤。此处示例:Filter graphql query in django
对 Adrien Answer 的补充很少。如果您想在过滤包含和完全匹配时执行不同的操作,请编辑您的 schema.py
class ApplicationNode(DjangoObjectType):
class Meta:
model = Application
# Provide more complex lookup types
filter_fields = {
'name': ['exact', 'icontains', 'istartswith']
}
interfaces = (relay.Node, )
你可以这样写查询
query {
allApplications(name_Icontains: "test") {
edges {
node {
id,
name
}
}
}
}