当属性被添加到 Python 中的 class 时执行方法

Perform method when an attribute is added to a class in Python

我想实例化一个类,比如 Fighter 有和没有属性 weapon_size。但是当设置属性 weapon_size 时(在实例化时或之后),我想运行一些添加另一个属性 damage 的方法(并且可能进行一些其他计算)。我试图通过重载 setattr 函数来实现这一点,如下所示。

我的问题:这是正确[且明智]的做法吗?

class Fighter(object):
    def __init__(self, prenom, weapon_size = None):
        self._prenom = prenom
        self._weapon_size = weapon_size
        if not weapon_size is None:
            self.AddWeapon(weapon_size)

    def __setattr__(self, name, value):
            if name == "weapon_size":
                print "Adding weapon"
                self.AddWeapon(value)
                self.__dict__['_' + name] = value
            else:
                self.__dict__[name] = value

    def AddWeapon(self, x):
        self._damage = x/2.

    @property
    def weapon_size(self):
        "Weapon size"
        return self._weapon_size
    @property
    def prenom(self):
        "First name"
        return self._prenom

U = Fighter('Greg')
U.weapon_size = 9
print U.weapon_size, U._damage
>> 9 4.5
W = Fighter('Jeff', weapon_size = 11)
print W.weapon_size, W._damage
>> 11 5.5

您可以为特定的 属性 定义自定义 setter。

@weapon_size.setter
def weapon_size(self, value):
    # custom code here
    self._weapon_size = value

编辑:但实际上,归根结底,我认为简单地做对您来说更干净:

class Fighter(object):
    def __init__(self, prenom, weapon_size=None):
        ...
        self.weapon_size = weapon_size
        ...

    @property
    def damage(self):
        if self.weapon_size:
            return self.weapon_size / 2
        return None