获取 Table 选择和相同形式的文件 POST

Question

我有一个 django 模板，其中包含一个 django_table2 table，并且还接受一个文件：

{% extends 'portal/base.html' %}
{% load render_table from django_tables2 %}
{% block title %}{{user.first_name }} {{ user.last_name }} Portal{% endblock %}

{% block content %}

    <input type=button value="Back" onClick="javascript:history.go(-1);">
    <h4>Currently registered vehicles:</h4>
    <div class='vehlist'>
        <form action="/loadlocndb/" method="POST">
            {% csrf_token %}
            {% render_table veh_list %}


            <h4> Location database .csv file</h4>
            <input type="file" name="myfile"><br/>
            <input type="submit" value="Submit" />
        </form>
    </div>
{% endblock %}

目前 POST 中唯一传回的是选中的 table 复选框。我如何也传回文件。

views.py

@login_required   
def locndb(request):
    # This is the basic user landing Page
    veh_list =VehicleTable(Vehicle.objects.filter(company__user=request.user))
    form = LocnDBForm()
    RequestConfig(request).configure(veh_list)
    return render(request, 'portal/locndb.html', {"veh_list": veh_list, "form": form})

@login_required   
def loadlocndb(request):


    if request.method == "POST":
        pks = request.POST.getlist("update")
        print pks
        selected_objects = Vehicle.objects.filter(pk__in=pks)

        vlist = []
        for i in selected_objects:
            vlist.append(i)

        return render(request, 'portal/loadlocndb.html',{"vlist":vlist})

forms.py

from django import forms
from django.contrib.auth.models import User
from portal.models import UserProfile, Vehicle

class UserForm(forms.ModelForm):
    password = forms.CharField(widget=forms.PasswordInput())

    class Meta:
        model = User
        fields = ('username', 'email', 'password')

class UserProfileForm(forms.ModelForm):
    class Meta:
        model = UserProfile
        fields = ('milkco', 'compName')

class LocnDBForm(forms.ModelForm):
    class Meta:
        model = Vehicle
        fields = ('vehid','locndb',)

车型

class Vehicle(models.Model):
    vehid = models.CharField(max_length = 10)
    company = models.ForeignKey(UserProfile, default = 1)
    #depot = models.ForeignKey(Depot, default = 1)
    locndb = models.FileField(upload_to="optiload/", default= "setting.MEDIA_ROOT/locndb/LocnDB.csv")

    class Meta:
        db_table = "vehicle"

    def __unicode__(self):
        return self.vehid

更好的是如何在不选择 table 中的至少一个条目以及一个文件的情况下阻止用户进行处理。

谢谢

Answer 1

我更新了您的 loadlocndb 视图：

@login_required   
def loadlocndb(request):


if request.method == "POST":
    pks = request.POST.getlist("update")

    myfile = request.FILES['form_field_name'].file
    print pks, myfile

    selected_objects = Vehicle.objects.filter(pk__in=pks)

    vlist = []
    for i in selected_objects:
        vlist.append(i)

    return render(request, 'portal/loadlocndb.html',{"vlist":vlist})

我还没有测试过，但是这个：request.FILES['form_field_name'].file 将从您的表单中获取文件。只需将您的文件表单字段名称替换为 'form_field_name'.

你能把你的代码从你的form.py吗？

并且在您的模板中，您应该将 <form action="/loadlocndb/" method="POST"> 替换为 <form action="/loadlocndb/" method="POST" enctype="multipart/form-data">。

来自 documentation：请注意，如果请求方法是 POST 且发布请求的 <form> 具有属性 enctype=[，则 request.FILES 将仅包含数据=28=]。否则，request.FILES 将为空。

获取 Table 选择和相同形式的文件 POST

Get Table selection and File in same form POST

html

python

django

file-upload

django-tables2