如何进行正确的 HQL 连接

Question

嗨，Whosebug 社区，

我在处理 HQL 查询时遇到问题。对于金融应用程序，我们希望获得基于给定 StrategyInstrument 实体的 TradeTicket 实体。以下是定义的实体（省略细节，仅显示关系）。

@Entity
public class Trade {
    @ManyToOne
    private Ticket ticket;

    @ManyToOne
    private Order buyOrder;

    @ManyToOne
    private Order sellOrder;
    ...
}

@Entity 
public class TradeTicket {
    private Date modifiedDateTime;
    ...
}

@Entity
public class Order {
    @OneToOne
    private StrategyInstrument strategyInstrument;
    ...
}

@Entity
public class StrategyInstrument {
    ...
}

然后我尝试以下查询：

String queryString = "select ticket from TradeTicket ticket"
    + " join Trade trade"
    + " join Order order"
    + " where trade.tradeTicket = ticket"
    + " and (trade.buyOrder = order or trade.sellOrder = order)"
    + " and order.strategyInstrument = :strategyInstrument"
    + " and ticket.clearingApproval.approved = true"
    + " order by ticket.modifiedDateTime";
List<TradeTicket> results = getSession()
    .createQuery(queryString)
    .setParameter("strategyInstrument", strategyInstrument)
    .list();

这会导致以下异常：

Caused by: org.hibernate.hql.ast.QuerySyntaxException: unexpected token: Order near line 1, column 102 [select ticket from com.mycompany.model.transactional.TradeTicket ticket join Trade trade   join Order order where trade.tradeTicket = ticket and (trade.buyOrder = order or trade.sellOrder = order) and order.strategyInstrument = :strategyInstrument and ticket.clearingApproval.approved = true order by ticket]
    at org.hibernate.hql.ast.QuerySyntaxException.convert(QuerySyntaxException.java:54)
    at org.hibernate.hql.ast.QuerySyntaxException.convert(QuerySyntaxException.java:47)
    at org.hibernate.hql.ast.ErrorCounter.throwQueryException(ErrorCounter.java:82)
    at org.hibernate.hql.ast.QueryTranslatorImpl.parse(QueryTranslatorImpl.java:284)
    at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:182)
    at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:136)
    at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:101)
    at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:80)
    at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:98)
    at org.hibernate.impl.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:156)
    at org.hibernate.impl.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:135)
    at org.hibernate.impl.SessionImpl.createQuery(SessionImpl.java:1760)

关于我的 HQL 有什么问题的任何线索？

谢谢，

何塞

Answer 1

order 是保留的 JPQL 和 SQL 关键字。更改您的实体名称。

你的语法也不对。加入 HQL 使用实体之间的关联。正确的语法是例如

select ticket from Trade trade
join trade.ticket ticket

Answer 2

Order是保留字；尝试使用其他东西。

Answer 3

这些人是正确的，Order 已保留，但不要更改您的实体名称，请尝试在 table 的定义中使用反引号。

@Entity
@Table(name="`Order`")
public class Order {`

来源： Hibernate Jira

如何进行正确的 HQL 连接

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