SQLAlchemy 条件过滤中的抽象
Abstraction in SQLAlchemy conditional filtering
我已经为我的数据库创建了模型:
class Album(db.Model):
id = db.Column(db.Integer, primary_key=True)
title = db.Column(db.String(128))
year = db.Column(db.String(4))
tracklist = db.relationship('Track', secondary=tracklist,
backref=db.backref('albums',
lazy='dynamic'), lazy='dynamic')
class Track(db.Model):
id = db.Column(db.Integer, primary_key=True)
title = db.Column(db.String(128))
class Artist(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(128))
releases = db.relationship('Track', secondary=releases,
backref=db.backref('artists',
lazy='dynamic'), lazy='dynamic')
他们是多对多相关的专辑<-->曲目<-->艺术家
接下来,我有这个表格:
class SearchForm(FlaskForm):
search_by_album = StringField('Album', validators=[Optional()])
search_by_artist = StringField('Artist', validators=[Optional()])
search_track = StringField('Track', validators=[Optional()])
year = StringField('Year', validators=[Optional(), Length(max=4)])
我的想法是让用户自由地填写所需的表单组合(但至少需要一个),所以我得到了这个函数,它接收 SearchForm().data(一个不可变的字典 'field_name': 'data'):
def construct_query(form):
query = db.session.query(*[field.label.text for field in form if field.data and field.name != 'csrf_token'])
if form.search_by_album.data:
query = query.filter(Album.title == form.search_by_album.data)
if form.search_by_artist.data:
query = query.filter(Artist.name == form.search_by_artist.data)
if form.search_track.data:
query = query.filter(Track.title == form.search_track.data)
if form.year.data:
query = query.filter(Album.year == form.year.data)
result = query.all()
return result
我的问题是在上面的函数中是否有更抽象的方法来添加过滤器?如果有一天我决定向我的表中添加更多列(甚至创建新表),我将不得不向 constrcut_query() 添加更多可怕的 ifs,这最终会变得非常庞大。或者这样的抽象不是 pythonic 方式,因为 "Explicit is better than implicit"?
PS
我知道模型中的表格,但我认为它们不是我的情况
一种方法是将过滤器属性与某个地方的字段相关联,例如作为表单本身的 class 属性:
class SearchForm(FlaskForm):
search_by_album = StringField('Album', validators=[Optional()])
search_by_artist = StringField('Artist', validators=[Optional()])
search_track = StringField('Track', validators=[Optional()])
year = StringField('Year', validators=[Optional(), Length(max=4)])
# map form fields to database fields/attributes
field_to_attr = {search_by_album: Album.title,
search_by_artist: Artist.name,
search_track: Track.title,
year: Album.year}
构建查询时,您可以以一种非常舒适的方式构建 where 子句:
def construct_query(form):
query = db.session.query(*[field.label.text for field in form if field.data and field.name != 'csrf_token'])
for field in form:
if field.data:
query = query.filter(form.field_to_attr[field] == field.data)
# or:
# for field, attr in form.field_to_attr.items():
# if field.data:
# query = query.filter(attr == field.data)
result = query.all()
return result
添加新字段和属性以进行筛选只会转化为创建字段及其到属性的映射。
我已经为我的数据库创建了模型:
class Album(db.Model):
id = db.Column(db.Integer, primary_key=True)
title = db.Column(db.String(128))
year = db.Column(db.String(4))
tracklist = db.relationship('Track', secondary=tracklist,
backref=db.backref('albums',
lazy='dynamic'), lazy='dynamic')
class Track(db.Model):
id = db.Column(db.Integer, primary_key=True)
title = db.Column(db.String(128))
class Artist(db.Model):
id = db.Column(db.Integer, primary_key=True)
name = db.Column(db.String(128))
releases = db.relationship('Track', secondary=releases,
backref=db.backref('artists',
lazy='dynamic'), lazy='dynamic')
他们是多对多相关的专辑<-->曲目<-->艺术家
接下来,我有这个表格:
class SearchForm(FlaskForm):
search_by_album = StringField('Album', validators=[Optional()])
search_by_artist = StringField('Artist', validators=[Optional()])
search_track = StringField('Track', validators=[Optional()])
year = StringField('Year', validators=[Optional(), Length(max=4)])
我的想法是让用户自由地填写所需的表单组合(但至少需要一个),所以我得到了这个函数,它接收 SearchForm().data(一个不可变的字典 'field_name': 'data'):
def construct_query(form):
query = db.session.query(*[field.label.text for field in form if field.data and field.name != 'csrf_token'])
if form.search_by_album.data:
query = query.filter(Album.title == form.search_by_album.data)
if form.search_by_artist.data:
query = query.filter(Artist.name == form.search_by_artist.data)
if form.search_track.data:
query = query.filter(Track.title == form.search_track.data)
if form.year.data:
query = query.filter(Album.year == form.year.data)
result = query.all()
return result
我的问题是在上面的函数中是否有更抽象的方法来添加过滤器?如果有一天我决定向我的表中添加更多列(甚至创建新表),我将不得不向 constrcut_query() 添加更多可怕的 ifs,这最终会变得非常庞大。或者这样的抽象不是 pythonic 方式,因为 "Explicit is better than implicit"?
PS 我知道模型中的表格,但我认为它们不是我的情况
一种方法是将过滤器属性与某个地方的字段相关联,例如作为表单本身的 class 属性:
class SearchForm(FlaskForm):
search_by_album = StringField('Album', validators=[Optional()])
search_by_artist = StringField('Artist', validators=[Optional()])
search_track = StringField('Track', validators=[Optional()])
year = StringField('Year', validators=[Optional(), Length(max=4)])
# map form fields to database fields/attributes
field_to_attr = {search_by_album: Album.title,
search_by_artist: Artist.name,
search_track: Track.title,
year: Album.year}
构建查询时,您可以以一种非常舒适的方式构建 where 子句:
def construct_query(form):
query = db.session.query(*[field.label.text for field in form if field.data and field.name != 'csrf_token'])
for field in form:
if field.data:
query = query.filter(form.field_to_attr[field] == field.data)
# or:
# for field, attr in form.field_to_attr.items():
# if field.data:
# query = query.filter(attr == field.data)
result = query.all()
return result
添加新字段和属性以进行筛选只会转化为创建字段及其到属性的映射。