如何让 python 脚本在 10 秒后自行停止?
How can I make a python script stop itself after 10 seconds?
我正在做一个我自己的项目,涉及 raspberry pi 上的伺服系统。我在执行代码时让它们旋转,但我更希望 python 脚本在 10 秒后自行终止,而不是一直按 CTRL + C。有没有办法用这个特定的代码来做到这一点?
import RPi.GPIO as GPIO
import time
GPIO.setmode(GPIO.BOARD)
GPIO.setup(7,GPIO.OUT)
try:
while True:
GPIO.output(7,1)
time.sleep(0.0015)
GPIO.output(7,0)
time.sleep(0.01)
except KeyboardInterrupt:
print"Stopping Auto-Feeder"
GPIO.cleanup()
尝试如下操作:
import RPi.GPIO as GPIO
import time
stop_time = time.time() + 10
GPIO.setmode(GPIO.BOARD)
GPIO.setup(7,GPIO.OUT)
try:
while time.time() < stop_time:
GPIO.output(7,1)
time.sleep(0.0015)
GPIO.output(7,0)
time.sleep(0.01)
except KeyboardInterrupt:
pass
print"Stopping Auto-Feeder"
GPIO.cleanup()
试试这个
wait = 10
while wait > 0:
print(wait)
time.sleep(1)
wait = wait - 1```
我正在做一个我自己的项目,涉及 raspberry pi 上的伺服系统。我在执行代码时让它们旋转,但我更希望 python 脚本在 10 秒后自行终止,而不是一直按 CTRL + C。有没有办法用这个特定的代码来做到这一点?
import RPi.GPIO as GPIO
import time
GPIO.setmode(GPIO.BOARD)
GPIO.setup(7,GPIO.OUT)
try:
while True:
GPIO.output(7,1)
time.sleep(0.0015)
GPIO.output(7,0)
time.sleep(0.01)
except KeyboardInterrupt:
print"Stopping Auto-Feeder"
GPIO.cleanup()
尝试如下操作:
import RPi.GPIO as GPIO
import time
stop_time = time.time() + 10
GPIO.setmode(GPIO.BOARD)
GPIO.setup(7,GPIO.OUT)
try:
while time.time() < stop_time:
GPIO.output(7,1)
time.sleep(0.0015)
GPIO.output(7,0)
time.sleep(0.01)
except KeyboardInterrupt:
pass
print"Stopping Auto-Feeder"
GPIO.cleanup()
试试这个
wait = 10
while wait > 0:
print(wait)
time.sleep(1)
wait = wait - 1```