升级到 Spark 2.0 dataframe.map

Question

我正在将一些 Spark 1.6 代码更新到 2.0.1，并且我运行遇到了一些使用地图的问题。

我看到其他关于 SO 问题的问题，例如，但我无法让这些技术发挥作用，它们对于下面的这种情况来说似乎很荒谬。

val df = spark.sqlContext.read.parquet(inputFile)
df: org.apache.spark.sql.DataFrame = [device_id: string, hour: string ... 9 more fields]

val deviceAggDF = df.select("device_id").distinct
deviceAggDF: org.apache.spark.sql.Dataset[org.apache.spark.sql.Row] = [device_id: string]

deviceAggDF.map( x =>
  (
    Map("ID" -> x.getAs[String](0)),
    Map()
  )
)
scala.MatchError: Nothing (of class scala.reflect.internal.Types$ClassNoArgsTypeRef)
  at org.apache.spark.sql.catalyst.ScalaReflection$.schemaFor(ScalaReflection.scala:667)
  at org.apache.spark.sql.catalyst.ScalaReflection$.toCatalystArray(ScalaReflection.scala:448)
  at org.apache.spark.sql.catalyst.ScalaReflection$.org$apache$spark$sql$catalyst$ScalaReflection$$serializerFor(ScalaReflection.scala:482)
  at org.apache.spark.sql.catalyst.ScalaReflection$$anonfun.apply(ScalaReflection.scala:592)
  at org.apache.spark.sql.catalyst.ScalaReflection$$anonfun.apply(ScalaReflection.scala:583)
  at scala.collection.TraversableLike$$anonfun$flatMap.apply(TraversableLike.scala:241)
  at scala.collection.TraversableLike$$anonfun$flatMap.apply(TraversableLike.scala:241)
  at scala.collection.immutable.List.foreach(List.scala:381)
  at scala.collection.TraversableLike$class.flatMap(TraversableLike.scala:241)
  at scala.collection.immutable.List.flatMap(List.scala:344)
  at org.apache.spark.sql.catalyst.ScalaReflection$.org$apache$spark$sql$catalyst$ScalaReflection$$serializerFor(ScalaReflection.scala:583)
  at org.apache.spark.sql.catalyst.ScalaReflection$.serializerFor(ScalaReflection.scala:425)
  at org.apache.spark.sql.catalyst.encoders.ExpressionEncoder$.apply(ExpressionEncoder.scala:61)
  at org.apache.spark.sql.Encoders$.product(Encoders.scala:274)
  at org.apache.spark.sql.SQLImplicits.newProductEncoder(SQLImplicits.scala:47)

Answer 1

要return空Map你应该指定可以ecnode的类型，例如：

deviceAggDF.map( x =>
  (
    Map("ID" -> x.getAs[String](0)),
    Map[String, String]()
  )
)

Map() 是 Map[Nothing,Nothing]，不能用于 Dataset。

升级到 Spark 2.0 dataframe.map

Upgrading to Spark 2.0 dataframe.map

apache-spark

elasticsearch-hadoop