xsd:attribute 声明在全局 xsd:complexType 中的什么位置？

Question

我想声明一个已经定义的元素的属性。我希望元素 person 可以有 2 个属性（name、id）我有这个：

<xs:element name="person" type="perso" />

<xs:complexType name="perso">
 <!-- I tried to declare the attribute here.Not working-->
        <xs:sequence>
            <!-- I tried to declare the attribute here.Not working-->
            <xs:element name="description" type="xs:string" />
        </xs:sequence>
</xs:complexType>

我希望声明一个全局而非局部的复杂类型。我对混合内容不感兴趣。

我收到的错误消息：

element attribute: Schemas parser error : Element '{http://www.w3.org/2001/XMLSchema}sequence': The content is not valid. Expected is (annotation?, (element | group | choice | sequence | any)*).

Answer 1

属性声明在 xs:sequence:

之后

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
  <xs:element name="person" type="perso" />
  <xs:complexType name="perso">
    <xs:sequence>
      <xs:element name="description" type="xs:string" />
    </xs:sequence>
    <xs:attribute name="name" type="xs:string"/>
    <xs:attribute name="id" type="xs:string"/>
  </xs:complexType>
</xs:schema>

xsd:attribute 声明在全局 xsd:complexType 中的什么位置？

Where does xsd:attribute declaration go in global xsd:complexType?

xml

xsd

xml-validation

xsd-validation