Hibernate Cascade 来自另一个数据库的另一个 Id
Hibernate Cascade another Id from another database
例如,我有 class A 级联到 B:
public class A{
private String id;
private Set<B> bs = new HashSet<B>(0);
@Id
@GenericGenerator(name = "seq_id", strategy = generators.SequenceIdGenerator")
@GeneratedValue(generator = "seq_id")
@COLUMN(name="id" unique = true, nullable = false, length = 28)
public void getId(){
return this.id;
}
@OneToMany(fetch = FetchType.LAZY, mappedBy = "A")
@Cascade({CascadeType.SAVE_UPDATE, CascadeType.DELETE, CascadeType.PERSIST})
public void getBs(){
return bs;
}
}
我有 B,它有自己的 ID 和一个包含来自 A
的 ID 的列
public class B
String id;
String aId;
A a;
@Id
@GenericGenerator(name = "seq_id", strategy = "generators.SequenceIdGenerator")
@GeneratedValue(generator = "seq_id")
@Column(name = "ID", unique = true, nullable = false, length = 28)
public String getId() {
return this.id;
}
@Column(name = "A_ID", nullable = false, length = 28)
public String getAId() {
return aId;
}
public void setAId(String aId) {
this.aId = aId;
}
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "A_ID", nullable = false, insertable = false, updatable = false)
@MapsId("aId")
public Admission getAdmission() {
return this.admission;
}
public void setAdmission(Admission admission) {
this.admission = admission;
}
如何在保存 A 时自动分配 aId?我想设置 aId,但我总是收到一条错误消息,指出 A_ID 不能设置为 null。
谢谢!
在共享映射中使用派生标识符时,您不仅需要在关系中添加 @MapsId
注释,还需要使用 @Id
注释对引用关系 ID 的字段进行注释。
查看操作方法(已省略 setter):
public class B {
String id;
String aId;
A a;
@Id
@GenericGenerator(name = "seq_id", strategy = "generators.SequenceIdGenerator")
@GeneratedValue(generator = "seq_id")
@Column(name = "ID", unique = true, nullable = false, length = 28)
public String getId() {
return this.id;
}
@Id
public String getAId() {
return aId;
}
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "A_ID", nullable = false)
@MapsId("aId")
public A getA() {
return this.a;
}
}
另一个错误是您将关系注释为 updatable = false
和 insertable = false
,这使得持久性提供程序忽略了将该字段写入数据库。
例如,我有 class A 级联到 B:
public class A{
private String id;
private Set<B> bs = new HashSet<B>(0);
@Id
@GenericGenerator(name = "seq_id", strategy = generators.SequenceIdGenerator")
@GeneratedValue(generator = "seq_id")
@COLUMN(name="id" unique = true, nullable = false, length = 28)
public void getId(){
return this.id;
}
@OneToMany(fetch = FetchType.LAZY, mappedBy = "A")
@Cascade({CascadeType.SAVE_UPDATE, CascadeType.DELETE, CascadeType.PERSIST})
public void getBs(){
return bs;
}
}
我有 B,它有自己的 ID 和一个包含来自 A
的 ID 的列public class B
String id;
String aId;
A a;
@Id
@GenericGenerator(name = "seq_id", strategy = "generators.SequenceIdGenerator")
@GeneratedValue(generator = "seq_id")
@Column(name = "ID", unique = true, nullable = false, length = 28)
public String getId() {
return this.id;
}
@Column(name = "A_ID", nullable = false, length = 28)
public String getAId() {
return aId;
}
public void setAId(String aId) {
this.aId = aId;
}
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "A_ID", nullable = false, insertable = false, updatable = false)
@MapsId("aId")
public Admission getAdmission() {
return this.admission;
}
public void setAdmission(Admission admission) {
this.admission = admission;
}
如何在保存 A 时自动分配 aId?我想设置 aId,但我总是收到一条错误消息,指出 A_ID 不能设置为 null。
谢谢!
在共享映射中使用派生标识符时,您不仅需要在关系中添加 @MapsId
注释,还需要使用 @Id
注释对引用关系 ID 的字段进行注释。
查看操作方法(已省略 setter):
public class B {
String id;
String aId;
A a;
@Id
@GenericGenerator(name = "seq_id", strategy = "generators.SequenceIdGenerator")
@GeneratedValue(generator = "seq_id")
@Column(name = "ID", unique = true, nullable = false, length = 28)
public String getId() {
return this.id;
}
@Id
public String getAId() {
return aId;
}
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "A_ID", nullable = false)
@MapsId("aId")
public A getA() {
return this.a;
}
}
另一个错误是您将关系注释为 updatable = false
和 insertable = false
,这使得持久性提供程序忽略了将该字段写入数据库。