Php Preg_Match 获取数组中带引号的字符串

Question

需要获取数组中带引号的字符串和不带引号的字符串

示例数据

$string='tennissrchkey1 tennissrchkey2 "tennis srch key 3" "tennis srch key 4" "tennis srch key 5"';

期望的输出

Array
(
    [0] => tennissrchkey1
    [1] => tennissrchkey2
    [2] => tennis srch key 3
    [3] => tennis srch key 4
    [4] => tennis srch key 5
)

到目前为止尝试过这个但还没有成功

if (preg_match('/"([^"]+)"/', $string, $m)) {
    echo '<pre>';
    print_r($m);   
} else {
   //preg_match returns the number of matches found, 
   //so if here didn't match pattern
}

非常感谢任何帮助！！！

谢谢！！！

Answer 1

<?php
    $sString = 'tennissrchkey1 tennissrchkey2 "tennis srch key 3" "tennis srch key 4" "tennis srch key 5"';

    $aTmp = explode( ' "', $sString );
    $iCountPieces = count( $aTmp );
    for( $i = 0; $i < $iCountPieces; ++$i )
    {
        $aFormatted[] = trim( $aTmp[ $i ], '"' );
    }
    var_dump( $aFormatted );
?>

Answer 2

使用preg_match_all函数进行全局匹配。 (?|....) 调用了 branch reset group。分支重置组内的备选方案共享相同的捕获组。

$re = '~(?|"([^"]*)"|(\S+))~m';
$str = 'tennissrchkey1 tennissrchkey2 "tennis srch key 3" "tennis srch key 4" "tennis srch key 5"';
preg_match_all($re, $str, $matches);
print_r($matches[1]);

DEMO

输出：

Array
(
    [0] => tennissrchkey1
    [1] => tennissrchkey2
    [2] => tennis srch key 3
    [3] => tennis srch key 4
    [4] => tennis srch key 5
)

Php Preg_Match 获取数组中带引号的字符串

Php Preg_Match to get Quoted string in array

php

arrays

string

preg-match