Pandas

Question

我有以下数据框：

**flashtalking_df =**

+--------------+--------------------------+------------------------+
| Placement ID | Average Interaction Time | Total Interaction Time |
+--------------+--------------------------+------------------------+
|      2041083 | 00:01:04.12182           | 24:29:27.500           |
|      2041083 | 00:00:54.75043           | 52:31:48.89108         |
+--------------+--------------------------+------------------------+

其中 00:01:04.12182 = HH:MM:SS.F

我需要将 Average Interaction Time 和 Total Interaction Time 这两个列都转换为秒数。

问题是总交互时间超过 24 小时。

我发现以下代码大部分都有效。但是，当总交互时间超过 24 小时时，它给了我

ValueError: time data '24:29:27.500' does not match format '%H:%M:%S.%f'

这是我目前正在使用的函数，它是我从另一个 Stack Overflow 问题中获取的，用于平均交互时间和总交互时间：

flashtalking_df['time'] = flashtalking_df['Total Interaction Time'].apply(lambda x: datetime.datetime.strptime(x,'%H:%M:%S.%f'))
flashtalking_df['timedelta'] = flashtalking_df['time'] - datetime.datetime.strptime('00:00:00.00000','%H:%M:%S.%f')
flashtalking_df['Total Interaction Time'] = flashtalking_df['timedelta'].apply(lambda x: x / np.timedelta64(1, 's'))

如果有更简单的方法，请告诉我。

感谢大家的帮助

Answer 1

我认为你需要先转换 to_timedelta and then to seconds by astype:

df['Average Interaction Time'] = pd.to_timedelta(df['Average Interaction Time'])
                                   .astype('timedelta64[s]')
                                   .astype(int)

df['Total Interaction Time'] =   pd.to_timedelta(df['Total Interaction Time'])
                                   .astype('timedelta64[s]')
                                   .astype(int)
                                   .map('{:,.2f}'.format)
print (df)
   Placement ID  Average Interaction Time Total Interaction Time
0       2041083                        64              88,167.00
1       2041083                        54             189,108.00

total_seconds, thank you 的解决方案：

df['Average Interaction Time'] = pd.to_timedelta(df['Average Interaction Time'])
                                   .dt.total_seconds()
                                   .map('{:,.2f}'.format)
df['Total Interaction Time'] =   pd.to_timedelta(df['Total Interaction Time'])
                                   .dt.total_seconds()
                                   .map('{:,.2f}'.format)

print (df)   
   Placement ID Average Interaction Time Total Interaction Time
0       2041083                    64.12              88,167.50
1       2041083                    54.75             189,108.89

Pandas - 将 HH:MM:SS.F 字符串转换为秒 - 注意：HH 有时超过 24H

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date

datetime

seconds