SQLite 从 2 个连接中获得一个 MAX

Question

我想从第一个 table（葡萄酒）中获得 2 table 的分数（品酒、评分）。 1 种葡萄酒可以拥有多次品尝和评级。

结构:

table wines
-----------
id 
name

table tastings
-------------
id 
wine_id
date
score

table ratings
-------------
id
wine_id
date
score

场景：1 种葡萄酒有 2 次不同日期和评分的品鉴，以及 3 次不同日期和评分的评分。

我想获得最后一次品尝（MAX 日期）和分数，以及最后评级（MAX 日期）和分数的葡萄酒。

示例数据：

Wines:
-----
id: 1
name: Beaulieu Vineyard

tastings:
--------
id: 1
wine_id: 1
date: 2014-01-01
score: 4
-
id: 2
wine_id: 1
date: 2015-02-02
score: 5

ratings:
--------
id: 1
wine_id: 1
date: 2013-04-04
score: 6
-
id: 2
wine_id: 1
date: 2014-05-05
score: 7
-
id: 3
wine_id: 1
date: 2015-06-06
score: 8

所以想要的结果是：

Beaulieu Vineyard | Tasting: 2015-02-02 - score: 5 | Rating: 2015-06-06 - score: 8

我当前有效的查询：

SELECT   
wines.winery,  
MAX(tastings.date) AS tasting_date,
MAX(ratings.date) AS rating_date
FROM wines    
LEFT JOIN tastings ON wines.id = tastings.wine_id AND tastings.status=1  
LEFT JOIN ratings ON wines.id = ratings.wine_id AND ratings.status=1  
WHERE wines.status = 1   
GROUP BY wines.id    
ORDER BY wines.winery

问题是当我试图获得与每次品尝和每次配对相关的正确分数时：

SELECT   
wines.winery,  
MAX(tastings.date) AS tasting_date, tastings.score,
MAX(ratings.date) AS rating_date, ratings.score
FROM wines    
LEFT JOIN tastings ON wines.id = tastings.wine_id AND tastings.status=1  
LEFT JOIN ratings ON wines.id = ratings.wine_id AND ratings.status=1  
WHERE wines.status = 1   
GROUP BY wines.id    
ORDER BY wines.winery

分数错误：结果显示的分数与MAX(date)对应的分数不正确。

Answer 1

SQLite 可以从匹配 MAX() 的行中获取值，但这仅在存在单个 MAX() 时有效。

您必须使用子查询来查找值：

SELECT winery,
       (SELECT MAX(date)
        FROM tastings
        WHERE wine_id = wines.id
          AND status = 1
       ) AS tasting_date,
       (SELECT score
        FROM tastings
        WHERE wine_id = wines.id
          AND status = 1
        ORDER BY date DESC
        LIMIT 1
       ) AS tasting_score,
       (SELECT MAX(date)
        FROM ratings
        WHERE wine_id = wines.id
          AND status = 1
       ) AS rating_date,
       (SELECT score
        FROM ratings
        WHERE wine_id = wines.id
          AND status = 1
        ORDER BY date DESC
        LIMIT 1
       ) AS rating_score,
FROM wines
WHERE status = 1
ORDER BY winery

或者，在进行分组之前查找最大日期：

SELECT wines.winery,
       tasting_date,
       tastings.score,
       rating_date,
       ratings.score
FROM wines
LEFT JOIN (SELECT wine_id AS id,
                  MAX(date) AS tasting_date,
                  score
           FROM tastings
           WHERE status = 1
           GROUP BY wine_id
          ) AS tastings USING (id)
LEFT JOIN (SELECT wine_id AS id,
                  MAX(date) AS rating_date,
                  score
           FROM ratings
           WHERE status = 1
           GROUP BY wine_id
          ) AS ratings USING (id)
WHERE wines.status = 1
ORDER BY wines.winery

SQLite 从 2 个连接中获得一个 MAX

SQLite obtain a MAX from 2 joins

sqlite

join

max

所以想要的结果是：