Scala case class 当你有 not-used-in-equals 属性时实例化
Scala case class instantiate when you have not-used-in-equals properties
有学术成就class：
case class A3(name: String)(val s: String) {}
正在尝试实例化它。我试过了
val v = A3("la")val v = A3("la", "ba")
我用谷歌搜索但找不到答案。
Scala IDE 消息没有帮助（更正：他们有帮助，但工具提示框不够大且背景为黑色，错过了重要部分，请参阅下面的 REPL 输出）。 REPL 帮助，需要使用两组括号，如：
val v = A3("ga")("mu")
完整回复：
scala> case class A3(name: String)(var s : String) {} defined class A3
scala> val v3 = A3("a2") :13: error: missing argument list
for method apply in object A3 Unapplied methods are only converted to
functions when a function type is expected. You can make this
conversion explicit by writing apply _ or apply(_)(_) instead of
apply.
val v3 = A3("a2")
^
scala> val v3 = A3("a2")("s") v3: A3 = A3(a2)
有学术成就class：
case class A3(name: String)(val s: String) {}
正在尝试实例化它。我试过了
val v = A3("la")val v = A3("la", "ba")
我用谷歌搜索但找不到答案。
Scala IDE 消息没有帮助（更正：他们有帮助，但工具提示框不够大且背景为黑色，错过了重要部分，请参阅下面的 REPL 输出）。 REPL 帮助，需要使用两组括号，如：
val v = A3("ga")("mu")
完整回复：
scala> case class A3(name: String)(var s : String) {} defined class A3
scala> val v3 = A3("a2") :13: error: missing argument list for method apply in object A3 Unapplied methods are only converted to functions when a function type is expected. You can make this conversion explicit by writing
apply _orapply(_)(_)instead ofapply. val v3 = A3("a2") ^scala> val v3 = A3("a2")("s") v3: A3 = A3(a2)