Scala 类型不匹配映射

Question

我正在尝试创建一个搜索功能，以便用户可以使用键值搜索列表，但是我尝试使用的方法 returns 类型不匹配，已删除不必要的代码并显示需要什么。我如何设置点以采用 Int 而不是 "Any"？

"type Any does not conform to type Int"

  val mapdata = readFile("data.txt")


  def handleTwo(): Boolean = {
    mnuShowPointsForTeam(currentPointsForTeam)
    true
  }




def mnuShowPointsForTeam(f: (String) => (String, Int)) = {
    print("Team>")
    val data = f(readLine)
    println(s"${data._1}: ${data._2}")
  }



  def currentPointsForTeam(team: String): (String, Int) = {
    val points = mapdata.get(team) match{
      case Some(p) => p
      case None => 0
    }
    (team, points)
  }

data.txt

SK1, 9, 7, 2, 0, 7, 3, 7, 9, 1, 2, 8, 1, 9, 6, 5, 3, 2, 2, 7, 2, 8, 5, 4, 5, 1, 6, 5, 2, 4, 1
SK2, 0, 7, 6, 3, 3, 3, 1, 6, 9, 2, 9, 7, 8, 7, 3, 6, 3, 5, 5, 2, 9, 7, 3, 4, 6, 3, 4, 3, 4, 1
SK4, 2, 9, 5, 7, 0, 8, 6, 6, 7, 9, 0, 1, 3, 1, 6, 0, 0, 1, 3, 8, 5, 4, 0, 9, 7, 1, 4, 5, 2, 8
SK5, 2, 6, 8, 0, 3, 5, 5, 2, 5, 9, 4, 5, 3, 5, 7, 8, 8, 2, 5, 9, 3, 8, 6, 7, 8, 7, 4, 1, 2, 3
SK6, 2, 7, 5, 9, 1, 9, 8, 4, 1, 7, 3, 7, 0, 8, 4, 5, 9, 2, 4, 4, 8, 7, 9, 2, 2, 7, 9, 1, 6, 9
SK7, 6, 9, 5, 0, 0, 0, 0, 5, 8, 3, 8, 7, 1, 9, 6, 1, 5, 3, 4, 7, 9, 5, 5, 9, 1, 4, 4, 0, 2, 0
SK8, 2, 8, 8, 3, 1, 1, 0, 8, 5, 9, 0, 3, 1, 6, 8, 7, 9, 6, 7, 7, 0, 9, 5, 2, 5, 0, 2, 1, 8, 6
SK9, 7, 1, 8, 8, 4, 4, 2, 2, 7, 4, 0, 6, 9, 5, 5, 4, 9, 1, 8, 6, 3, 4, 8, 2, 7, 9, 7, 2, 6, 6

Answer 1

您似乎想要 return 一个带有 List[Int] 的元组，而不仅仅是一个 Int.

如果是

def currentPointsForTeam(team: String): (String, List[Int]) = 
  (team, mapdata.get(team).getOrElse(List.empty))
    // Or maybe List(0) instead of List.empty

如果您确实想要 return 单个 Int，则必须说明如何从映射中的 List[Int] 变为单个值。也许是一笔钱？

def currentPointsForTeam(team: String): (String, Int) = 
  (team, mapdata.get(team).map(_.sum).getOrElse(0))

Scala 类型不匹配映射

Scala Type Mismatch Mapping

scala

mismatch