Swift 3 更新表示调用函数之间的时间间隔的变量

Question

我创建了一个函数，它每 27 秒调用一次。调用变量的代码如下

_ = Timer.scheduledTimer(timeInterval: time, target: self, selector: #selector(GameScene.method), userInfo: nil, repeats: true)

变量time在函数方法中乘以0.95但变量时间仍然没有更新。

Answer 1

timeInterval 你用 scheduledTimer 指定的那个预定的 Timer 对象保持不变，如果你想改变时间，那么你需要像这样在调用函数中再次安排它.

 _ = Timer.scheduledTimer(timeInterval: time, target: self, selector: #selector(GameScene.method), userInfo: nil, repeats: false)

 func method() {
     //Do your task
     time += 0.95 //increase timer
     //Schedule it again
     _ = Timer.scheduledTimer(timeInterval: time, target: self, selector: #selector(GameScene.method), userInfo: nil, repeats: false)
 }

Answer 2

func increaseTime() {

   time += 0.95 // This will increase the time by 0.95 every time this function is called

   // Then call the function again to update the time
   _ = Timer.scheduledTimer(timeInterval: time, target: self, selector: #selector(GameScene.method), userInfo: nil, repeats: true)

}

确保您的变量是 var 而不是 let 或 const，因为常量变量无法编辑。

Swift 3 更新表示调用函数之间的时间间隔的变量

Swift 3 Update the variable which represents the time interval between a function being called

swift

function

time

swift3

nstimer