在 C/glib 中将 guint8 转换为 uint32_t
Convert guint8 to uint32_t in C/glib
我找不到在 C
中将 guint8 转换为 uint32_t 的方法
我试过了:
uint32_t *uint32_value = (uint32_t *)guint8_value;
但它说:
warning: cast to pointer from integer of different size [-Wint-to-pointer-cast]
uint32_t *uint32_value = (uint32_t *)guint8_value
^
warning: assignment makes integer from pointer without a cast [-Wint-conversion]
uint32_t *uint32_value = (uint32_t *)guint8_value
^
您不是从 guint8
投射到 uint32_t
。
您正在从整数 (guint8
) 转换为指向整数 (uint32_t*
) 的指针
正确的代码很简单:
uint32_t uint32_value = guint8_value;
我找不到在 C
中将 guint8 转换为 uint32_t 的方法我试过了:
uint32_t *uint32_value = (uint32_t *)guint8_value;
但它说:
warning: cast to pointer from integer of different size [-Wint-to-pointer-cast]
uint32_t *uint32_value = (uint32_t *)guint8_value
^
warning: assignment makes integer from pointer without a cast [-Wint-conversion]
uint32_t *uint32_value = (uint32_t *)guint8_value
^
您不是从 guint8
投射到 uint32_t
。
您正在从整数 (guint8
) 转换为指向整数 (uint32_t*
) 的指针
正确的代码很简单:
uint32_t uint32_value = guint8_value;