将两个浮点值字典除以零值

Question

我有除法错误的问题。我使用两个字典，我必须将它们除以其他字典。但有些值为 0。我不想出错，但我想要

我的两个字典：

问题垃圾邮件：

  {0: [3.75199226626618e-79], 1: [1.0384638247478166e-25], 2: [3.876104531640006e-157]}

问题：

 {0: [1.0143598477460146e-78], 1: [0.0], 2: [2.2740883119510355e-138]}

错误函数：

def bayes (probspam, probham):
    try:
        lista={k: [probspam[k][0]/probham[k][0]] for k in probham}
    except ZeroDivisionError:
        k=0
    return lista

我怎么能告诉我的系统，当probham[k]=0时，它应该将除法结果赋值为0而不是给我："ZeroDivisionError: float division by zero"?

Answer 1

是您要找的吗？

def bayes (probspam, probham):
    lista={k: [probspam[k][0]/probham[k][0] if probham[k][0] !=0 else .0] for k in probham}
    return lista

或者，如果您需要 0.0 而不是 [0.0] 作为值

def bayes (probspam, probham):
    lista={k: [probspam[k][0]/probham[k][0]] if probham[k][0] !=0 else .0 for k in probham}
    return lista

List/dict感悟强大！ :)

Answer 2

试试这个：

def bayes(probspam, probham):
    lista = {}
    for k in probham:
        if probham[k][0] != 0:
            lista[k] = [probspam[k][0]/probham[k][0]]
        else:
            lista[k] = [0.0]

    return lista

将两个浮点值字典除以零值

Divide two dictionaries of float values with zero values

python

floating-point

dictionary

division

divide-by-zero