我可以为 Python 中的继承方法创建别名吗？

Question

我的 Python 程序中有一个非常复杂的 class 层次结构。该程序有很多工具，要么是模拟器，要么是编译器。这两种方法共享一些方法，因此有一个 Shared class 作为所有 class 的基础 class。精简示例如下所示：

class Shared:
  __TOOL__ = None

  def _Prepare(self):
    print("Preparing {0}".format(self.__TOOL__))


class Compiler(Shared):
  def _Prepare(self):
    print("do stuff 1")
    super()._Prepare()
    print("do stuff 2")

  def _PrepareCompiler(self):
    print("do stuff 3")
    self._Prepare()
    print("do stuff 4")


class Simulator(Shared):
  def _PrepareSimulator(self):   # <=== how to create an alias here?
    self._Prepare()           


class Tool1(Simulator):
  __TOOL__ = "Tool1"

  def __init__(self):
    self._PrepareSimulator()

  def _PrepareSimulator(self):
    print("do stuff a")
    super()._PrepareSimulator()
    print("do stuff b")

我可以将方法 Simulator._PrepareSimulator 定义为 Simulator/Shared._Prepare 的别名吗？

我知道我可以创建本地别名，例如：__str__ = __repr__，但在我的情况下，_Prepare 在上下文中是未知的。我没有 self 也没有 cls 来引用这个方法。

我可以为 return _Prepare 而不是 _PrepareSimulator 编写装饰器吗？但是我如何在装饰器中找到 _Prepare？

我是否也需要调整方法绑定？

Answer 1

我设法创建了一个基于装饰器的解决方案，它确保了类型安全。第一个装饰器注释了本地方法的别名。需要它来保护别名目标。需要第二个装饰器来替换 Alias 实例并检查别名是否指向类型层次结构中的方法。

装饰器/别名定义：

from inspect import getmro

class Alias:
  def __init__(self, method):
    self.method = method

  def __call__(self, func):
    return self

def HasAliases(cls):
  def _inspect(memberName, target):
    for base in getmro(cls):
      if target.__name__ in base.__dict__:
        if (target is base.__dict__[target.__name__]):
          setattr(cls, memberName, target)
          return
      else:
        raise NameError("Alias references a method '{0}', which is not part of the class hierarchy: {1}.".format(
          target.__name__, " -> ".join([base.__name__ for base in getmro(cls)])
        ))

  for memberName, alias in cls.__dict__.items():
    if isinstance(alias, Alias):
      _inspect(memberName, alias.method)

  return cls

用法示例：

class Shared:
  __TOOL__ = None

  def _Prepare(self):
    print("Preparing {0}".format(self.__TOOL__))


class Shared2:
  __TOOL__ = None

  def _Prepare(self):
    print("Preparing {0}".format(self.__TOOL__))


class Compiler(Shared):
  def _Prepare(self):
    print("do stuff 1")
    super()._Prepare()
    print("do stuff 2")

  def _PrepareCompiler(self):
    print("do stuff 3")
    self._Prepare()
    print("do stuff 4")


@HasAliases
class Simulator(Shared):
  @Alias(Shared._Prepare)
  def _PrepareSimulatorForLinux(self):    pass

  @Alias(Shared._Prepare)
  def _PrepareSimulatorForWindows(self):  pass


class Tool1(Simulator):
  __TOOL__ = "Tool1"

  def __init__(self):
    self._PrepareSimulator()

  def _PrepareSimulator(self):
    print("do stuff a")
    super()._PrepareSimulatorForLinux()
    print("do stuff b")
    super()._PrepareSimulatorForWindows()
    print("do stuff c")

t = Tool1()

将 @Alias(Shared._Prepare) 设置为 @Alias(Shared2._Prepare) 将引发异常：

NameError: Alias references a method '_Prepare', which is not part of the class hierarchy: Simulator -> Shared -> object.

我可以为 Python 中的继承方法创建别名吗？

Can I create an alias to an inherited method in Python?

python

methods

alias

python-3.x

python-decorators