ISO-8601 字符串的 Unix 时间戳

Question

我有一个名为 ACQDATA 的 Oracle table，它有一个字段 READDATETIME，我在其中存储一个以毫秒为单位的 Unix 时间戳作为 INTEGER (NUMBER(38))类型。

SQL> select READDATETIME from ACQDATA where ID=1000;

READDATETIME
____________
   1.4793E+12

我需要 select 该值作为 ISO-8601 字符串 (YYYY-MM-DDTHH:MM:SS.mmm):

SQL> select READDATETIME from ACQDATA where ID=1000;

READDATETIME
-------------------
   1.4793E+12

我试过使用 TO_CHAR 转换它，但结果很乱：

   SQL> select TO_CHAR(TO_DATE('1970-01-01','YYYY-MM-DD') + NUMTODSINTERVAL(READDATETIME, 'SECOND'), 'YYYY-MM-DD HH24:MI:SS') from ACQDATA where ID=1000;

Error at line 1:
ORA-01873: the leading precision of the interval is too small

感谢帮助。

Answer 1

您的 readdatetime 似乎以毫秒为单位。 Oracle 日期算法以天为基础，因此您需要将该数字转换为它代表的天数；一天是 86400 秒，所以是 86400000 毫秒:

with acqdata (id, readdatetime) as (
  select 1000, 1479318995000 from dual
)
select to_char(date '1970-01-01' + (READDATETIME/86400000), 'YYYY-MM-DD"T"HH24:MI:SS')
from ACQDATA where ID=1000;

TO_CHAR(DATE'1970-0
-------------------
2016-11-16T17:56:35

T 添加为 a character literal。

SQL 开发人员默认以科学记数法显示如此大的数字。您可以使用 set numformat 更改默认值，或使用 to_char() 显示整个值：

select readdatetime, to_char(readdatetime, '9999999999999') as string
from ACQDATA where ID=1000;

READDATETIME STRING        
------------ --------------
  1.4793E+12  1479318995000

如果您的值有小数秒，所以最后三位数字不是零，您可以将日期转换为时间戳并添加小数部分；这还添加了 UTC 'Z' 指标以供娱乐：

with acqdata (id, readdatetime) as (
  select 1000, 1479300462063 from dual
)
select to_char(cast(date '1970-01-01' + (readdatetime/86400000) as timestamp)
    + numtodsinterval(remainder(readdatetime, 1000)/1000, 'SECOND'),
  'YYYY-MM-DD"T"HH24:MI:SS.FF3"Z"')
from acqdata where id=1000;

TO_CHAR(CAST(DATE'1970-01-01'+
------------------------------
2016-11-16T12:47:42.063Z

或者没有中间 date 值，从时间戳文字开始：

with acqdata (id, readdatetime) as (
  select 1000, 1479300462063 from dual
)
select to_char(timestamp '1970-01-01 00:00:00'
  + numtodsinterval(readdatetime/1000, 'SECOND'),
  'YYYY-MM-DD"T"HH24:MI:SS.FF3"Z"')
from acqdata where id=1000;

TO_CHAR(TIMESTAMP'1970-0
------------------------
2016-11-16T12:47:42.063Z

正如@Wernfried 指出的那样，最好明确表明纪元时间是从 UTC 开始的：

alter session set time_zone='America/New_York';

with acqdata (readdatetime) as (
  select 1479300462063 from dual
  union all select 1467331200000 from dual
  union all select 1467648000000 from dual
)
select readdatetime,
  to_char(timestamp '1970-01-01 00:00:00' + numtodsinterval(readdatetime/1000, 'SECOND'),
    'YYYY-MM-DD"T"HH24:MI:SS.FF3') as implicit,
  to_char(cast(timestamp '1970-01-01 00:00:00' as timestamp with time zone)
    + numtodsinterval(readdatetime/1000, 'SECOND'),
    'YYYY-MM-DD"T"HH24:MI:SS.FF3TZH:TZM') as local_offset,
  to_char(timestamp '1970-01-01 00:00:00 UTC' + numtodsinterval(readdatetime/1000, 'SECOND'),
    'YYYY-MM-DD"T"HH24:MI:SS.FF3TZH:TZM') as utc_offset,
  to_char(timestamp '1970-01-01 00:00:00 UTC' + numtodsinterval(readdatetime/1000, 'SECOND'),
    'YYYY-MM-DD"T"HH24:MI:SS.FF3TZR') as utc
from acqdata;

  READDATETIME IMPLICIT                LOCAL_OFFSET                  UTC_OFFSET                    UTC                       
-------------- ----------------------- ----------------------------- ----------------------------- --------------------------
 1479300462063 2016-11-16T12:47:42.063 2016-11-16T12:47:42.063-05:00 2016-11-16T12:47:42.063+00:00 2016-11-16T12:47:42.063UTC
 1467331200000 2016-07-01T00:00:00.000 2016-07-01T01:00:00.000-04:00 2016-07-01T00:00:00.000+00:00 2016-07-01T00:00:00.000UTC
 1467648000000 2016-07-04T16:00:00.000 2016-07-04T17:00:00.000-04:00 2016-07-04T16:00:00.000+00:00 2016-07-04T16:00:00.000UTC

Answer 2

Alex 的回答并不完全正确。 Unix 时间戳始终基于 1970-01-01 00:00:00 UTC

除非您的会话在 UTC 时区运行，否则精确的解决方案如下：

select 
   TO_CHAR((TIMESTAMP '1970-01-01 00:00:00 UTC' + readdatetime/1000 * INTERVAL '1' SECOND) AT LOCAL, 'YYYY-MM-DD"T"HH24:MI:SS.FF3')
from ACQDATA where ID=1000;

或

select 
   TO_CHAR((TIMESTAMP '1970-01-01 00:00:00' AT TIME ZONE 'UTC' + readdatetime/1000 * INTERVAL '1' SECOND) AT LOCAL, 'YYYY-MM-DD"T"HH24:MI:SS.FF3')
from ACQDATA where ID=1000;

或者如果您更喜欢函数而不是文字：

select 
   TO_CHAR((TO_TIMESTAMP_TZ('1970-01-01 00:00:00 UTC', 'YYYY-MM-DD HH24:MI:SS TZR') + numtodsinterval(readdatetime/1000, 'SECOND')) AT LOCAL, 'YYYY-MM-DD"T"HH24:MI:SS.FF3')
from ACQDATA where ID=1000;

ISO-8601 字符串的 Unix 时间戳

Unix Timestamp to ISO-8601 String

oracle

timestamp

iso8601