两个 table 之间的关系，中间有一个可选的第三个 table

Question

我有以下架构和数据。

--drop table table_c;
--drop table table_b;
--drop table table_a;

create table table_a (
  id    number(3,0)  primary key,
  value varchar2(10)
);

create table table_b (
  id    number(3,0)  primary key,
  a_id  number(3,0)  not null,
  value varchar2(10),
  constraint b_fk1 foreign key (a_id) references table_a(id)
);

create table table_c (
  id    number(3,0)  primary key,
  a_id  number(3,0)  null,
  b_id  number(3,0)  null,
  value varchar2(10),
  constraint c_fk1 foreign key (a_id) references table_a(id),
  constraint c_fk2 foreign key (b_id) references table_b(id)
);

-- table a
insert into table_a (id, value) values (1, 'a');
insert into table_a (id, value) values (2, 'b');
-- table b
insert into table_b (id, a_id, value) values (1, 1, 'aa');
insert into table_b (id, a_id, value) values (2, 2, 'bb');
-- table c with ref to a
insert into table_c (id, a_id, value) values (1, 1, 'aaa');
insert into table_c (id, a_id, value) values (2, 2, 'bbb');
-- table c with ref to b
insert into table_c (id, b_id, value) values (3, 1, 'ccc');
insert into table_c (id, b_id, value) values (4, 2, 'ddd');
COMMIT;

如果我们没有从 table_c 到 link 的直接 link 的话，它基本上是 table_a 和 table_c 之间的关系，有一条通过 table_b 的路线table_a.

table_c 中的每个元素将填充 a_id 或 b_id。如果我们有 a_id，我们就没有 b_id。如果我们有 b_id，我们就没有 a_id。两者不能同时为 null，也不能同时为非空。

现在我被要求创建一个物化视图来显示 table_a 和 table_c 之间的关系。

我的第一个想法是更新 table_c 以便 a_id 始终是最新的。客户对数据库有很强的控制力，禁止我这样做！

--drop materialized view mv_d;
--drop materialized view log on table_c;
--drop materialized view log on table_b;
--drop materialized view log on table_a;

create materialized view log on table_a with rowid, sequence;
create materialized view log on table_b with rowid, sequence;
create materialized view log on table_c with rowid, sequence;

create materialized view mv_d
  refresh fast on commit
  enable query rewrite
  as
    select a.value as a_val,
           c.value as c_val,
           a.rowid as a_rowid,
           b.rowid as b_rowid,
           c.rowid as c_rowid
      from table_a a,
           table_b b,
           table_c c
     where (c.a_id is null and c.b_id = b.id and b.a_id = a.id)
        or (c.a_id is not null and c.a_id = a.id);

execute dbms_stats.gather_table_stats( user, 'mv_d' ) ;

我对这个 mv 的问题是结果不是我所期望的。这就是我得到的。请注意，rowid 被缩写以显示它们的差异和实际结果，这意味着它们重复的原因。

select * from mv_d;

-- note, the rowids are for information only, but are abbreviated to only show how they're different.
 a_val | c_val | a_rowid | b_rowid | c_rowid
-------+-------+---------+---------+---------
 a     | aaa   | GAAA    | WAAA    | mAAA
 a     | ccc   | GAAA    | WAAA    | mAAC
 a     | aaa   | GAAA    | WAAB    | mAAA
 b     | bbb   | GAAB    | WAAA    | mAAB
 b     | bbb   | GAAB    | WAAB    | mAAB
 b     | ddd   | GAAB    | WAAB    | mAAD

理想情况下，我会从 select * from mv_d 中得到以下结果（禁止 rowid 列，ofc）。

 a_val | c_val 
-------+-------
 a     | aaa   
 a     | ccc   
 b     | bbb   
 b     | ddd

如何在实体化视图中获得该结果？

请注意，我的实际数据库中 table_a、table_b、table_c 分别有 300 万、600 万和 100 万条记录。过滤所有内容的实际结果存在于具有大约 10k 条记录的物化视图中。

Answer 1

select      a.value as a_val
           ,c.value     as c_val
           ,a.rowid     as a_rowid
           ,b.rowid     as b_rowid
           ,c.rowid     as c_rowid

from                    table_a a

            join        (           table_c c

                        left join   table_b b

                        on          c.b_id  = b.id
                        )

            on           a.id = nvl (b.a_id,c.a_id) 

;

对于实体化视图，请使用旧样式代码

select      a.value as a_val
           ,c.value     as c_val
           ,a.rowid     as a_rowid
           ,b.rowid     as b_rowid
           ,c.rowid     as c_rowid

from        dmarkovitz.table_a a
           ,dmarkovitz.table_b b
           ,dmarkovitz.table_c c

where       c.b_id  = b.id (+)
        and a.id    = nvl (b.a_id,c.a_id) 
;

两个 table 之间的关系，中间有一个可选的第三个 table

Relation between two tables with an optional third table in between

sql

oracle

materialized-views