循环并仅获取状态是否为真
loop and only get status is if true
我想遍历此视图,并且只能在为真时获取状态,否则如果不为真,则将其显示在底部的另一个视图中。
<table class="rounded" >
Unavailable Requests
{{#each request in model}}
<ul>
<li> Trip ID: {{request.request_id}}</li>
<li> Destination: {{request.destination}}</li>
<li >Hotel Name: {{request.hotel_name}} - {{#link-to 'rfp' request.id}}view request{{/link-to}}
</li>
<li>Status: {{status}}</li>
<li>Client: {{request.full_name}} - ({{request.user.email}})</li>
</ul>
{{/each}}
</table>
App.DashboardRoute = App.AuthRoute.extend({
model: function(){
return this.store.find('request');
}
});
提前谢谢大家......
您可以像这样在模板中间放置一个 if
助手:
<table class="rounded" >
Unavailable Requests
{{#each request in model}}
<ul>
<li> Trip ID: {{request.request_id}}</li>
<li> Destination: {{request.destination}}</li>
<li >Hotel Name: {{request.hotel_name}} - {{link-to "view request" 'rfp' request}}</li>
{{#if status}}
Show the status
{{else}}
Show the other view
{{/if}}
<li>Client: {{request.full_name}} - ({{request.user.email}})</li>
</ul>
{{/each}}
</table>
我想遍历此视图,并且只能在为真时获取状态,否则如果不为真,则将其显示在底部的另一个视图中。
<table class="rounded" >
Unavailable Requests
{{#each request in model}}
<ul>
<li> Trip ID: {{request.request_id}}</li>
<li> Destination: {{request.destination}}</li>
<li >Hotel Name: {{request.hotel_name}} - {{#link-to 'rfp' request.id}}view request{{/link-to}}
</li>
<li>Status: {{status}}</li>
<li>Client: {{request.full_name}} - ({{request.user.email}})</li>
</ul>
{{/each}}
</table>
App.DashboardRoute = App.AuthRoute.extend({
model: function(){
return this.store.find('request');
}
});
提前谢谢大家......
您可以像这样在模板中间放置一个 if
助手:
<table class="rounded" >
Unavailable Requests
{{#each request in model}}
<ul>
<li> Trip ID: {{request.request_id}}</li>
<li> Destination: {{request.destination}}</li>
<li >Hotel Name: {{request.hotel_name}} - {{link-to "view request" 'rfp' request}}</li>
{{#if status}}
Show the status
{{else}}
Show the other view
{{/if}}
<li>Client: {{request.full_name}} - ({{request.user.email}})</li>
</ul>
{{/each}}
</table>