单击按钮后重置计数器

Question

在 DeleteTask 中，如果在 listView 中选中复选框，我有一个用于删除列表的按钮。

delete.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {

                int itemCount = listview.getCount();
                for (int i = itemCount - 1; i >= 0; i--) {
                    SearchList search = adapter.getItem(i);
                    if (search.isSelected()) {
                        adapter.removeItem(i);
                        delete.setText("DELETE");
                        counter=0;
                    }
                }
            }
        });

在DeleteAdapter中，它有一个计数器，用于对选中的框进行计数，并在button中显示该计数器。单击 delete button 后，计数器假设重置为 0，并且仅在 delete button setText 中显示 DELETE。

 holder.ckbox.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    if (((CheckBox) v).isChecked()) {
                        int getPosition = (Integer) v.getTag();  // Here we get the position that we have set for the checkbox using setTag.
                        search.get(getPosition).setSelected(((CheckBox)v).isChecked()); // Set the value of checkbox to maintain its state.
                        checkBoxCounter ++;
                        delete.setText("DELETE"+""+"("+ checkBoxCounter +")");
                    } else
                    {
                        int getPosition = (Integer) v.getTag();  // Here we get the position that we have set for the checkbox using setTag.
                        search.get(getPosition).setSelected(((CheckBox) v).isChecked()); // Set the value of checkbox to maintain its state.
                        checkBoxCounter--;
                        if (checkBoxCounter == 0) {
                            delete.setText("DELETE");
                        }
                        else {
                            delete.setText("DELETE" + "" + "(" + checkBoxCounter + ")");
                        }
                    }
                }
            });

我现在的问题是当点击删除按钮时，它显示 'DELETE'，但是当我选中复选框时，计数器没有重置。如何重置计数器？

编辑

我已将计数器更改为 checkBoxCounter，但仍然得到相同的结果！

 delete.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {

                int itemCount = listview.getCount();
                for (int i = itemCount - 1; i >= 0; i--) {
                    SearchList search = adapter.getItem(i);
                    if (search.isSelected()) {
                        adapter.removeItem(i);
                        delete.setText("DELETE");
                        checkBoxCounter=0;
                    }
                }
            }
        });

When I click button delete, the button shows DELETE. But, when I press another checkbox again, the counter starts from the last set value instead of 1.

请帮忙。

这是我的部分应用程序屏幕截图

https://i.stack.imgur.com/R954N.jpg

Answer 1

而不是 counter = 0 你需要做 checkBoxCounter = 0 inside delete click listener

Answer 2

分配 checkBoxCounter = 0 在 onClick() 函数内。为了安全起见，您可以更改代码如下，以避免从代码的其他部分更新 checkBoxCounter 。

 holder.ckbox.setOnClickListener(new View.OnClickListener() {
                @Override
                public void onClick(View v) {
                    if (((CheckBox) v).isChecked()) {
                        int getPosition = (Integer) v.getTag();  // Here we get the position that we have set for the checkbox using setTag.
                        search.get(getPosition).setSelected(((CheckBox)v).isChecked()); // Set the value of checkbox to maintain its state.
                        checkBoxCounter ++;
                        delete.setText("DELETE"+""+"("+ checkBoxCounter +")");
                    } else
                    {
                        int getPosition = (Integer) v.getTag();  // Here we get the position that we have set for the checkbox using setTag.
                        search.get(getPosition).setSelected(((CheckBox) v).isChecked()); // Set the value of checkbox to maintain its state.
                        checkBoxCounter--;
                        if (checkBoxCounter <= 0) {
                            delete.setText("DELETE");
                            checkBoxCounter = 0;
                        }
                        else {
                            delete.setText("DELETE" + "" + "(" + checkBoxCounter + ")");
                        }
                    }
                }
            });

Answer 3

如果有两个不同的classes，那么在适配器内部添加一个方法class来重置计数器。

可能是这样的：

内部适配器class，添加：

public void resetCheckedCounter(){
    checkBoxCounter = 0;
}

对于 "Delete" 按钮，添加：
```
adapter.resetCheckedCounter();
```

希望对您有所帮助！

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