MySql排除查询

Question

我有一个 table 看起来像这样

JOB_ID  | Email        | Type       | Date      
_____________________________________
28319   | mike@aol.com | Service    | 11-24-2016
_____________________________________ 
28412   | mike@aol.com | Rotation   | 11-24-2016
_____________________________________
38123   | andy@aol.com | Service    | 11-24-2016
_____________________________________
28199   | roger@aol.com| Service    | 11-24-2016

我会问运行 return 那些安排了服务但没有在特定日期轮换的人。

这是我的尝试：

SELECT j.Job_ID,j.Email,j.Type,j.Date
from Jobs j 
join
     Jobs  j2
     on j.Email = j2.Customer_Email
where j2.JOB_ID NOT IN (select j.JOB_ID
                  from Jobs j
                  where j.Type = 'Rotation'
                 )     AND j.Date = '11-24-2016';

所以我的查询是 return 安迪和罗杰。

Answer 1

这应该可以为您解决问题，这里不需要连接：

SELECT * FROM Jobs WHERE Date = '11-24-2016' AND Type = 'Service' AND 
Email NOT IN (SELECT Email FROM Jobs WHERE Date = '11-24-2016' AND 
Type = 'Rotation');

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