计算 SQL 中的连续班次和天数

Question

我正在尝试显示团队工作的连续班次和天数。我尝试了很多解决方案，但总不能完全正确。

数据是日期、班次、船员。有一个日班和夜班和 3 个工作人员。 ConsecutiveShift 和 ConsecutiveDay 是我要生成的字段。输出将用于根据连续 shifts/days 工作的次数查看生产力。

非常感谢任何帮助

Dateop               Shift  Crew
2015-12-23 00:00:00  D      B Crew
2015-12-23 00:00:00  N      A Crew
2015-12-24 00:00:00  D      B Crew
2015-12-24 00:00:00  N      A Crew
2015-12-25 00:00:00  D      C Crew
2015-12-25 00:00:00  N      B Crew
2015-12-26 00:00:00  D      C Crew
2015-12-26 00:00:00  N      B Crew
2015-12-27 00:00:00  D      C Crew
2015-12-27 00:00:00  N      B Crew
2015-12-28 00:00:00  D      C Crew
2015-12-28 00:00:00  N      B Crew
2015-12-29 00:00:00  D      C Crew
2015-12-29 00:00:00  N      B Crew
2015-12-30 00:00:00  D      A Crew
2015-12-30 00:00:00  N      C Crew
2015-12-31 00:00:00  D      A Crew
2015-12-31 00:00:00  N      C Crew
2016-01-01 00:00:00  D      A Crew
2016-01-01 00:00:00  N      C Crew
2016-01-02 00:00:00  D      A Crew
2016-01-02 00:00:00  N      C Crew

期望输出 - 前 3 列是原始数据，第 4 列和第 5 列是我要生成的计数

Answer 1

以下查询应该有效，使用 window 函数：

With cte As (
    Select DateOp, Shift, Crew,
        DateDiff(Day, DateOp, '2016-01-01') + Row_Number() Over (Partition By Crew, Shift Order By DateOp) As ShiftIsland,
        DateDiff(Day, DateOp, '2016-01-01') + Row_Number() Over (Partition By Crew Order By DateOp) As DayIsland
      From [YourTable])      
Select DateOp, Shift, Crew,
    Row_Number() Over (Partition By Crew, Shift, ShiftIsland Order By DateOp) As ConsecutiveShifts,
    Row_Number() Over (Partition By Crew, DayIsland Order By DateOp) As ConsecutiveDays
  From cte
  Order By Crew, DateOp, Shift;

Answer 2

我认为这是一个基本的row_number()。对于您提供的数据：

select t.*,
       row_number() over (partition by shift, crew order by date) as consecutiveshift,
       row_number() over (partition by crew order by date) as consecutiveday
from t;

这至少 returns 您问题中的数据。

计算 SQL 中的连续班次和天数

Counting consecutive shift and days in SQL

sql

sql-server

sql-server-2012

recursive-query

gaps-and-islands