自动 Hibernate 索引创建时间过长

Question

我带着 bug/problem 回来了，现在阳光明媚了。通常我会在 H2DB 上测试本地开发和更改，但据我所知，这也必须适用于 Oracle 和 MSSQL。现在再次在oracle上测试出现了这个问题：密钥 COR_VIEWSETTINGSCOR_USERSETTINGS_FK0 和 COR_VIEWSETTINGSCOR_USERSETTINGS_FK1 是自动生成的，对于 oracle 数据库来说太长了。为了了解这些键是如何创建的，我现在将向您展示实体 UserSettings 和 UserViewSettings。提示：如果它们让您感到困惑，您可以忽略这些实体并进一步进行编辑。也许你还能帮我。

用户设置

/**

      The Class UserSettings.

*/
@org.hibernate.envers.Audited
@DataObject( value =  UserSettings.DATA_OBJECT_NAME )
@CRUDDefinition( supportsRead = true, supportsCreate = true, supportsUpdate = true, supportsDelete = true )
@Entity( name = UserSettings.DATA_OBJECT_NAME )
@NamedQuery( name = UserSettings.DATA_OBJECT_NAME, query = "from userSettings e where e.name = :name" )
@javax.persistence.Inheritance( strategy = javax.persistence.InheritanceType.TABLE_PER_CLASS )
@AttributeOverrides( { @AttributeOverride( name = "id", column = @Column( name = "USERSETTINGS_ID" ) )
} )
@Table( name = "COR_USERSETTINGS", indexes = {
  @javax.persistence.Index( name="COR_USERSETTINGS_FK0", columnList = "SETTINGSTYPE_ID" ),
  @javax.persistence.Index( name="COR_USERSETTINGS_FK1", columnList = "USER_ID" ),
}
)
public class UserSettings extends NamedRevisionEntity implements NameSettingsType, NameSettings
{
  /** The Constant serialVersionUID. */
  private static final long serialVersionUID = 1L;

  /** The Constant DATA_OBJECT_NAME. */
  public static final String DATA_OBJECT_NAME = "userSettings";

  @javax.persistence.Basic( fetch = javax.persistence.FetchType.EAGER, optional = false )
  @Column( name = "SETTINGS", nullable = false, unique = false, insertable = true, updatable = true )
  @javax.persistence.Lob
  private java.lang.String settings;

  @javax.persistence.ManyToOne( fetch = javax.persistence.FetchType.EAGER, optional = false )
  @javax.persistence.JoinColumn( name = "SETTINGSTYPE_ID", nullable = false, unique = false, insertable = true, updatable = true )
  private SettingsType settingsType;

  @javax.persistence.ManyToOne( fetch = javax.persistence.FetchType.EAGER, optional = true )
  @javax.persistence.JoinColumn( name = "USER_ID", nullable = true, unique = false, insertable = true, updatable = true )
  private User user;



  public SettingsType getSettingsType()
  {
    return settingsType;
  }

  public void setSettingsType( SettingsType settingsType )
  {
    this.settingsType = settingsType;
  }

  public User getUser()
  {
    return user;
  }

  public void setUser( User user )
  {
    this.user = user;
  }

  public java.lang.String getSettings()
  {
    return settings;
  }

  public void setSettings( java.lang.String settings )
  {
    this.settings = settings;
  }

  @Override
  public String getDataObjectName()
  {
    return DATA_OBJECT_NAME;
  }



  @Override
  public String toString()
  {
    StringBuilder builder = new StringBuilder( super.toString() );

    builder.append( ", " );
    try
    {
        builder.append( ToStringUtils.referenceToString( "settingsType", "SettingsType", this.settingsType ) );
    }
    catch( Exception ex )
    {
      builder.append( ex.getClass().getName()  );
      builder.append( ": " );
      builder.append( ex.getMessage() );
    }
    builder.append( ", " );
    try
    {
        builder.append( ToStringUtils.referenceToString( "user", "User", this.user ) );
    }
    catch( Exception ex )
    {
      builder.append( ex.getClass().getName()  );
      builder.append( ": " );
      builder.append( ex.getMessage() );
    }

    builder.append( "]" );
    return builder.toString();
  }

}

用户视图设置

/**

      The Class UserViewSettings.

*/
@org.hibernate.envers.Audited
@DataObject( value =  UserViewSettings.DATA_OBJECT_NAME )
@CRUDDefinition( supportsRead = true, supportsCreate = true, supportsUpdate = true, supportsDelete = true )
@Entity( name = UserViewSettings.DATA_OBJECT_NAME )
@AttributeOverrides( { @AttributeOverride( name = "id", column = @Column( name = "VIEWSETTINGS_ID" ) )
} )
@Table( name = "COR_VIEWSETTINGS", uniqueConstraints = {
  @javax.persistence.UniqueConstraint( name="COR_VIEWSETTINGS_UNQ1", columnNames = { "NAME", "SETTINGSTYPE_ID", "VIEW_NAME", "VIEWTYPE_ID" } ),
}
, indexes = {
  @javax.persistence.Index( name="COR_VIEWSETTINGS_FK0", columnList = "VIEWTYPE_ID" ),
}
)
public class UserViewSettings extends UserSettings implements NameViewName, NameViewType
{
  /** The Constant serialVersionUID. */
  private static final long serialVersionUID = 1L;

  /** The Constant DATA_OBJECT_NAME. */
  public static final String DATA_OBJECT_NAME = "userViewSettings";

  @javax.persistence.Basic( fetch = javax.persistence.FetchType.EAGER, optional = false )
  @Column( name = "VIEW_NAME", nullable = false, unique = false, insertable = true, updatable = true )
  private java.lang.String viewName;

  @javax.persistence.ManyToOne( fetch = javax.persistence.FetchType.EAGER, optional = true )
  @javax.persistence.JoinColumn( name = "VIEWTYPE_ID", nullable = true, unique = false, insertable = true, updatable = true )
  private ViewType viewType;



  public java.lang.String getViewName()
  {
    return viewName;
  }

  public void setViewName( java.lang.String viewName )
  {
    this.viewName = viewName;
  }

  public ViewType getViewType()
  {
    return viewType;
  }

  public void setViewType( ViewType viewType )
  {
    this.viewType = viewType;
  }

  @Override
  public String getDataObjectName()
  {
    return DATA_OBJECT_NAME;
  }



  @Override
  public String toString()
  {
    StringBuilder builder = new StringBuilder( super.toString() );

    builder.append( ", " );
    builder.append( "viewName" );
    builder.append( "=" );
    builder.append( this.viewName );
    builder.append( ", " );
    try
    {
        builder.append( ToStringUtils.referenceToString( "viewType", "ViewType", this.viewType ) );
    }
    catch( Exception ex )
    {
      builder.append( ex.getClass().getName()  );
      builder.append( ": " );
      builder.append( ex.getMessage() );
    }

    builder.append( "]" );
    return builder.toString();
  }

}

使用 Hibernate 5.2 和 Oracle 11 数据库启动 Wildfly 10.0.0 然后导致自动生成的密钥 COR_VIEWSETTINGSCOR_USERSETTINGS_FK0 和 COR_VIEWSETTINGSCOR_USERSETTINGS_FK1对于数据库来说自然是太长了。

我查看了 Hibernate 的 NamingStrategies，甚至尝试了一些，但它们没有为我更改错误。

如何影响这些密钥的生成？

编辑：

所以打开 DEBUG 给了我这个：

2016-11-29 09:22:03,190 DEBUG [org.hibernate.SQL] (ServerService Thread Pool -- 58) create index COR_USERSETTINGS_FK0 on COR_USERSETTINGS (SETTINGSTYPE_ID)
2016-11-29 09:22:03,190 DEBUG [org.hibernate.SQL] (ServerService Thread Pool -- 58) create index COR_USERSETTINGS_FK1 on COR_USERSETTINGS (USER_ID)
2016-11-29 09:22:03,190 DEBUG [org.hibernate.SQL] (ServerService Thread Pool -- 58) create index COR_VIEWSETTINGSCOR_USERSETTINGS_FK0 on COR_VIEWSETT INGS(SETTINGSTYPE_ID)
2016-11-29 09:22:03,190 DEBUG [org.hibernate.SQL] (ServerService Thread Pool -- 58) create index COR_VIEWSETTINGSCOR_USERSETTINGS_FK1 on COR_VIEWSETTINGS (USER_ID)
2016-11-29 09:22:03,190 DEBUG [org.hibernate.SQL] (ServerService Thread Pool -- 58) create index COR_VIEWSETTINGS_FK0 on COR_VIEWSETTINGS (VIEWTYPE_ID)

现在我在包 org.hibernate.boot.model.naming 中找到了 Class ImplicitIndexNameSource 但是互联网并没有真正举例说明我可以用这个做什么，它似乎很长一段时间以来都是空的 class。

编辑 2：

之前的编辑好像走错了路。我找到了创建这些日志的地方。它是从 SchemaCreatorImpl 调用的 StandardIndexExporter。所以我需要更深入地研究框架，但如果有人看到了。这是正确的道路吗？我可以修改代码让他做我想做的事吗？这似乎是 hbm2ddl 的罪魁祸首，因为在这些行中在 StandardIndexExport 中创建了索引：

final String indexNameForCreation;
if ( dialect.qualifyIndexName() ) {
    indexNameForCreation = jdbcEnvironment.getQualifiedObjectNameFormatter().format(
            new QualifiedNameImpl(
                    index.getTable().getQualifiedTableName().getCatalogName(),
                    index.getTable().getQualifiedTableName().getSchemaName(),
                    jdbcEnvironment.getIdentifierHelper().toIdentifier( index.getName() )
            ),
            jdbcEnvironment.getDialect()
    );
}
else {
    indexNameForCreation = index.getName();
}
final StringBuilder buf = new StringBuilder()
        .append( "create index " )
        .append( indexNameForCreation )
        .append( " on " )
        .append( tableName )
        .append( " (" );

boolean first = true;
Iterator<Column> columnItr = index.getColumnIterator();
while ( columnItr.hasNext() ) {
    final Column column = columnItr.next();
    if ( first ) {
        first = false;
    }
    else {
        buf.append( ", " );
    }
    buf.append( ( column.getQuotedName( dialect ) ) );
}
buf.append( ")" );
return new String[] { buf.toString() };

非常感谢您的帮助。这真令人沮丧

Answer 1

所以我让它工作了。为未来可能发现此问题并遇到相同问题的人回答。

索引键是由hibernate引用的oracle方言创建的。所以必须要做的是实现一个自定义的 OracleDialect，它覆盖方法 getIndexExporter 并指向自定义的 IndexExporter。在此 IndexExporter 中，您可以修改键的创建方式。在我的例子中，我修复了这样的解决方案：

  /**
   * Gets the correct index name if it is a index for a TABLE_PER_CLASS inheritance and longer than
   * 30 chars.
   *
   * @param index the index to decide for
   * @return the correct index name
   */
  private String getCorrectIndexName( Index index )
  {
    if ( index.getTable() instanceof DenormalizedTable && index.getName().length() > 30 )
    {
      String prefixedTable = index.getTable().getName();
      String tableName = prefixedTable.substring( prefixedTable.indexOf( '_' ) + 1, prefixedTable.length() );
      tableName = shortenName( tableName );
      Iterator<Column> columnItr = index.getColumnIterator();
      String reference;

      if ( columnItr.hasNext() )
      {
        reference = extractReference( columnItr.next() );
      }
      else
      {
        /** backup strategy to prevent exceptions */
        reference = shortenName( NamingHelper.INSTANCE.hashedName( index.getName() ) );
      }

      return tableName + "_" + reference;
    }
    return index.getName();
  }

  /**
   * Extract the reference column of the index and hash the full name before shortening it with
   * shortenName().
   *
   * @param index the index to extract the reference from.
   * @return the reference with an appended _FK(hashedReference).
   */
  private String extractReference( Column column )
  {
    String reference = column.getQuotedName( dialect );
    String md5Hash = NamingHelper.INSTANCE.hashedName( reference );
    md5Hash = md5Hash.substring( md5Hash.length() - 4, md5Hash.length() );
    reference = shortenName( reference );

    return reference + "_FK" + md5Hash;
  }

  /**
   * Shorten the name to a maximum of 11 chars if it's longer.
   *
   * @param reference the reference to shorten
   * @return the shortened string
   */
  private static String shortenName( String reference )
  {
    if ( reference.length() > 11 )
    {
      return reference.substring( 0, 11 );
    }
    return reference;
  }

这必须在覆盖函数 getSqlCreateStrings 中调用。更改后的行如下所示：

  String indexName = getCorrectIndexName( index );
  indexNameForCreation = jdbcEnvironment.getQualifiedObjectNameFormatter()
      .format(
          new QualifiedNameImpl( index.getTable().getQualifiedTableName().getCatalogName(),
              index.getTable().getQualifiedTableName().getSchemaName(), jdbcEnvironment.getIdentifierHelper().toIdentifier( indexName ) ),
          jdbcEnvironment.getDialect() );

我希望对某人有所帮助。

自动 Hibernate 索引创建时间过长

Automatic Hibernate index creation too long

java

oracle

hibernate

hbm2ddl