按问题分组的普遍查询

Question

我正在尝试运行在普适数据库上进行此查询

select cust_no,cust_name,sum(bvtotal) as Amount
from sales_history_header  
where cust_no is not null and number is not null and bvtotal > 1000 and in_date < 20140101
group by cust_no,cust_name
order by sum(bvtotal) desc;

如何在子结果中排除 in_date > 20140101 的组结果？

我的这个查询也在获取 in_date > 20140101

的结果

我是不是做错了什么？

我得到的示例输出是这种格式

cust_no     cust_name      amount
A             a1            500
B             b1            500
C             c1            1000

我想用 cust_no 排除这条记录 'A' 因为它在 20140202

与 in_date 有过交易

在我的原始数据中考虑我有像

这样的记录

cust_no     cust_name      amount    in_date
A             a1            100      20130203
A             a1            400      20130101
A             a1            1000     20140503

Answer 1

我认为您需要将日期常量指定为日期，除非您真的想处理整数。

select cust_no,cust_name,sum(bvtotal) as Amount
from sales_history_header  
where cust_no is not null and number is not null and bvtotal > 1000 and in_date < '2014-01-01'
group by cust_no,cust_name
order by sum(bvtotal) desc;

Answer 2

我不明白你到底需要什么，

但您似乎混合了 INT 和 DATE 类型。

因此，如果您的 in_date 字段的类型为 DATE

select 
  cust_no,
  cust_name,
  sum(bvtotal) as Amount
from sales_history_header  
where cust_no is not null 
  and number is not null 
  and bvtotal > 1000 
  and in_date < DATE('2014-01-01')
group by cust_no,cust_name
order by sum(bvtotal) desc;

如果您的 in_date 字段的类型为 TIMESTAMP

select 
  cust_no,
  cust_name,
  sum(bvtotal) as Amount
from sales_history_header  
where cust_no is not null 
  and number is not null 
  and bvtotal > 1000 
  and in_date < TIMESTAMP('2014-01-01 00:00:00')
group by cust_no,cust_name
order by sum(bvtotal) desc;

Answer 3

您需要根据一组 ID 排除所有记录。通常，您使用子查询执行此操作：

SELECT cust_no,
    cust_name,
    sum(bvtotal) AS Amount
FROM sales_history_header
WHERE cust_no IS NOT NULL
    AND number IS NOT NULL
    AND bvtotal > 1000
    AND cust_no NOT IN (
        SELECT cust_no 
        FROM sales_history_header 
        WHERE in_date >= 20140101 
            AND cust_no IS NOT NULL
    )
GROUP BY cust_no,
    cust_name
ORDER BY sum(bvtotal) DESC;

子查询的 AND cust_no IS NOT NULL 部分是为了避免 NOT IN 和 NULL 值出现问题。如果将其重写为 NOT EXISTS 相关子查询，您可能会有更好的性能，但根据我的经验，MySQL 在这些方面非常糟糕。

另一种选择是更明确的自反加入方法（LEFT JOIN 和 filter where right table is null）但这有点……粗略的感觉？……因为你看起来允许 cust_no 成为 NULL 并且因为它是一个聚合查询所以感觉你必须担心乘法行：

SELECT s1.cust_no,
    s1.cust_name,
    sum(s1.bvtotal) AS Amount
FROM sales_history_header s1
LEFT JOIN (
        SELECT cust_no
        FROM sales_history_header
        WHERE cust_no IS NOT NULL
            AND number IS NOT NULL
            AND bvtotal > 1000
            AND in_date >= 20140101) s2
    ON  s2.cust_no = s1.cust_no
WHERE s1.cust_no IS NOT NULL
    AND s1.number IS NOT NULL
    AND s1.bvtotal > 1000
    AND s2.cust_no IS NULL
GROUP BY cust_no,
    cust_name
ORDER BY sum(bvtotal) DESC;

LEFT JOIN结合WHERE [...] s2.cust_no IS NULL是去掉不需要的记录的部分。

按问题分组的普遍查询

pervasive query with group by issue

mysql

sql

pervasive-sql