HTTP Post 请求 Android 开发 - 帮助调试
HTTP Post Request for Android Development - Help debugging
我正在尝试通过按钮访问 Apache 服务器。
我正在向服务器发送消息并接收返回消息。我正在文本字段中显示该消息。
我的代码不工作,我不知道如何调试。我附上了我的代码和 PHP 脚本。我是这方面的初学者,所以任何帮助将不胜感激。
public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
public void sendMessage(View view) {
HttpURLConnection request = null;
try {
String myURL = "http://creative.colorado.edu/";
URL url = new URL(myURL);
request = (HttpURLConnection) url.openConnection();
//To post output request
request.setDoOutput(true);
request.setRequestMethod("POST");
request.setRequestProperty("message", "text/plain");
String input = "I am ok";
OutputStream outputPost = new BufferedOutputStream(request.getOutputStream());
outputPost.write(input.getBytes());
outputPost.flush();
outputPost.close();
BufferedReader in = new BufferedReader(new InputStreamReader(request.getInputStream()));
String inputLine;
while((inputLine = in.readLine()) != null){
System.out.println(inputLine);
}
in.close();
System.out.println(inputLine);
TextView displayMessage = (TextView) findViewById(R.id.textView2);
displayMessage.setText(in.toString());
}
catch (Exception ex) {
}
finally {
if (request != null) {
request.disconnect();
}
}
}
}
这是我正在使用的 PHP 脚本(我不确定它是否正确):
<?php
//Read request parameters
$message= $_POST[“message”];
// Store values in an array
$returnValue = array(“message”=>$message);
// Send back request in JSON format
echo json_encode($returnValue);
?>
在从输入流中读取之前,您需要实际进行 http 调用。
...
outputPost.close();
request.connect()
BufferedReader in = new BufferedReader(new InputStreamReader(request.getInputStream()));
...
此外,任何网络调用都需要在后台异步线程中进行。 Volley (https://developer.android.com/training/volley/simple.html) 库使这项工作变得非常容易。
我正在尝试通过按钮访问 Apache 服务器。
我正在向服务器发送消息并接收返回消息。我正在文本字段中显示该消息。
我的代码不工作,我不知道如何调试。我附上了我的代码和 PHP 脚本。我是这方面的初学者,所以任何帮助将不胜感激。
public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
public void sendMessage(View view) {
HttpURLConnection request = null;
try {
String myURL = "http://creative.colorado.edu/";
URL url = new URL(myURL);
request = (HttpURLConnection) url.openConnection();
//To post output request
request.setDoOutput(true);
request.setRequestMethod("POST");
request.setRequestProperty("message", "text/plain");
String input = "I am ok";
OutputStream outputPost = new BufferedOutputStream(request.getOutputStream());
outputPost.write(input.getBytes());
outputPost.flush();
outputPost.close();
BufferedReader in = new BufferedReader(new InputStreamReader(request.getInputStream()));
String inputLine;
while((inputLine = in.readLine()) != null){
System.out.println(inputLine);
}
in.close();
System.out.println(inputLine);
TextView displayMessage = (TextView) findViewById(R.id.textView2);
displayMessage.setText(in.toString());
}
catch (Exception ex) {
}
finally {
if (request != null) {
request.disconnect();
}
}
}
}
这是我正在使用的 PHP 脚本(我不确定它是否正确):
<?php
//Read request parameters
$message= $_POST[“message”];
// Store values in an array
$returnValue = array(“message”=>$message);
// Send back request in JSON format
echo json_encode($returnValue);
?>
在从输入流中读取之前,您需要实际进行 http 调用。
...
outputPost.close();
request.connect()
BufferedReader in = new BufferedReader(new InputStreamReader(request.getInputStream())); ...
此外,任何网络调用都需要在后台异步线程中进行。 Volley (https://developer.android.com/training/volley/simple.html) 库使这项工作变得非常容易。