如果我不设置断点，将获得 EXC_BAD_access

Question

我得到了 EXC_BAD_access 这个代码

_emailID  = [NSMutableString stringWithString:self.txtEmail.text];
_password = [NSMutableString stringWithString:self.txtPassword.text];
 NSDictionary *params = @{@"email" : _emailID, @"password" : _password, @"device" : @"iOS"};

我已经启用僵尸模式，这就是我得到的

Thread 1: EXC_BREAKPOINT (code=EXC_i386_BPT, subcode=0x0) error

但是当我在 _emailID 行上放置一个断点并手动转到下一行时，它根本不会抛出错误

//View.h
@property (nonatomic, assign) NSMutableString *emailID;
@property (nonatomic, assign) NSMutableString *password;

//View.m
@synthesize emailID;
@synthesize password;

Answer 1

我试过你的代码，当我尝试打印字典时崩溃了。

我尝试像这样更改属性来解决此崩溃问题

@property (nonatomic, strong) NSMutableString *emailID;
@property (nonatomic, strong) NSMutableString *password;

其他代码如下

@synthesize emailID;
@synthesize password;

- (void)viewDidLoad {
    [super viewDidLoad];
    // Do any additional setup after loading the view.


    emailID  = [NSMutableString stringWithString:self.tfEmail.text];
    password = [NSMutableString stringWithString:self.tfPassword.text];
    NSDictionary *params = @{@"email" : emailID, @"password" : password, @"device" : @"iOS"};

    NSLog(@"%@",params);


}

而且有效！！

如果我不设置断点，将获得 EXC_BAD_access

Getting a EXC_BAD_access if I don't put a breakpoint

ios

objective-c

exc-bad-access