是否可以像 easylogging++ 一样通过链接重载的插入运算符来创建模仿 std::cout 语法的 C++ class?
Is it possible to create a C++ class that mimics the std::cout syntax by chaining overloaded insertion operators the same way that easylogging++ does?
easylogging++ 代码定义了一个宏,使用起来非常简单:
LOG(logLevel) << "This mimics std::cout syntax. " << 1 << " + " << 1 << " = " << 2;
我想为 easylogging++ 制作一个包装器 class。我可以很容易地创建一个带有两个参数的函数来包装上面的行。但是,是否可以在包装器 class 中模仿此语法?例如:
Logger logger;
logger(logLevel) << "Line " << 1 << " of log text.";
我知道我可以轻松地重载插入运算符,但这仍然让我每次都必须编写另一个函数来设置日志级别。
更新:
多亏了 Starl1ght 的回答,我才得以完成这项工作。我想我会分享以防其他人有类似的需求。
我创建了两个重载。一个用于 (),另一个用于 <<.
Logger &operator()(logLevelT logLevel) {
mLogLevel = logLevel;
return *this;
}
template <typename T>
Logger &operator<<(T const &value) {
LOG(mLogLevel) << value;
return *this;
}
更新 2:
我想再次更新此 post 以给出我的推理并展示我的最终解决方案。
我的理由是我的项目是抽象的演示。我试图证明日志库(以及许多其他东西)可以从软件的核心功能中抽象出来。这也使软件组件模块化。这样我就可以在不丢失语法的情况下换出 easylogging++ 库,因为它是在模块接口中实现的。
我上次更新没有提到我是如何克服插入链接的障碍的,所以我想 post 一个例子来说明我是如何做到的。以下代码是一个简化示例,说明如何为 class.
实现类似 std::cout 的语法
#include <iostream> // For cout
#include <string> // For strings
#include <sstream> // For ostringstream
enum logLevelT {
INFO_LEVEL,
WARNING_LEVEL,
ERROR_LEVEL,
FATAL_LEVEL
};
class Logger {
private:
std::string logName;
public:
Logger(std::string nameOfLog, std::string pathToLogFile) {
logName = nameOfLog;
//TODO Configure your logging library and instantiate
// an instance if applicable.
}
~Logger(){}
// LogInputStream is instantiated as a temporary object. It is used
// to build the log entry stream. It writes the completed stream
// in the destructor as the object goes out of scope automatically.
struct LogInputStream {
LogInputStream(logLevelT logLevel, std::string nameOfLog) {
currentLogLevel = logLevel;
currentLogName = nameOfLog;
}
// Copy Constructor
LogInputStream(LogInputStream &lis) {
currentLogLevel = lis.currentLogLevel;
currentLogName = lis.currentLogName;
logEntryStream.str(lis.logEntryStream.str());
}
// Destructor that writes the log entry stream to the log as the
// LogInputStream object goes out of scope.
~LogInputStream() {
std::cout << "Logger: " << currentLogName
<< " Level: " << currentLogLevel
<< " logEntryStream = " << logEntryStream.str()
<< std::endl;
//TODO Make a log call to your logging library. You have your log level
// and a completed log entry stream.
}
// Overloaded insertion operator that adds the given parameter
// to the log entry stream.
template <typename T>
LogInputStream &operator<<(T const &value) {
logEntryStream << value;
return *this;
}
std::string currentLogName;
logLevelT currentLogLevel;
std::ostringstream logEntryStream;
};
// Overloaded function call operator for providing the log level
Logger::LogInputStream operator()(logLevelT logLevel) {
LogInputStream logInputStream(logLevel, logName);
return logInputStream;
}
// Overloaded insertion operator that is used if the overloaded
// function call operator is not used.
template <typename T>
Logger::LogInputStream operator<<(T const &value) {
LogInputStream logInputStream(INFO_LEVEL, logName);
logInputStream << value;
return logInputStream;
}
};
int main(int argc, char *argv[]) {
Logger logger1 = Logger("Logger1", "/path/to/log.log");
Logger logger2 = Logger("Logger2", "/path/to/log.log");
logger1(INFO_LEVEL) << "This is the " << 1 << "st test";
logger2(ERROR_LEVEL) << "This is the " << 2 << "nd test";
logger2 << "This is the " << 3 << "rd test";
return 0;
}
我觉得我可以在命名和评论方面做得更好,但时间紧迫。我绝对愿意接受任何评论或批评。
你必须重载 operator()
这样,它会设置内部日志级别和 return *this
作为类型 Logger&
,所以重载 operator<<
会起作用在 returned 参考中设置了必要的日志级别。
像这样:
Logger& Logger::operator()(LogLevel level) {
// set internal log level
return *this;
}
easylogging++ 代码定义了一个宏,使用起来非常简单:
LOG(logLevel) << "This mimics std::cout syntax. " << 1 << " + " << 1 << " = " << 2;
我想为 easylogging++ 制作一个包装器 class。我可以很容易地创建一个带有两个参数的函数来包装上面的行。但是,是否可以在包装器 class 中模仿此语法?例如:
Logger logger;
logger(logLevel) << "Line " << 1 << " of log text.";
我知道我可以轻松地重载插入运算符,但这仍然让我每次都必须编写另一个函数来设置日志级别。
更新:
多亏了 Starl1ght 的回答,我才得以完成这项工作。我想我会分享以防其他人有类似的需求。
我创建了两个重载。一个用于 (),另一个用于 <<.
Logger &operator()(logLevelT logLevel) {
mLogLevel = logLevel;
return *this;
}
template <typename T>
Logger &operator<<(T const &value) {
LOG(mLogLevel) << value;
return *this;
}
更新 2:
我想再次更新此 post 以给出我的推理并展示我的最终解决方案。
我的理由是我的项目是抽象的演示。我试图证明日志库(以及许多其他东西)可以从软件的核心功能中抽象出来。这也使软件组件模块化。这样我就可以在不丢失语法的情况下换出 easylogging++ 库,因为它是在模块接口中实现的。
我上次更新没有提到我是如何克服插入链接的障碍的,所以我想 post 一个例子来说明我是如何做到的。以下代码是一个简化示例,说明如何为 class.
实现类似 std::cout 的语法#include <iostream> // For cout
#include <string> // For strings
#include <sstream> // For ostringstream
enum logLevelT {
INFO_LEVEL,
WARNING_LEVEL,
ERROR_LEVEL,
FATAL_LEVEL
};
class Logger {
private:
std::string logName;
public:
Logger(std::string nameOfLog, std::string pathToLogFile) {
logName = nameOfLog;
//TODO Configure your logging library and instantiate
// an instance if applicable.
}
~Logger(){}
// LogInputStream is instantiated as a temporary object. It is used
// to build the log entry stream. It writes the completed stream
// in the destructor as the object goes out of scope automatically.
struct LogInputStream {
LogInputStream(logLevelT logLevel, std::string nameOfLog) {
currentLogLevel = logLevel;
currentLogName = nameOfLog;
}
// Copy Constructor
LogInputStream(LogInputStream &lis) {
currentLogLevel = lis.currentLogLevel;
currentLogName = lis.currentLogName;
logEntryStream.str(lis.logEntryStream.str());
}
// Destructor that writes the log entry stream to the log as the
// LogInputStream object goes out of scope.
~LogInputStream() {
std::cout << "Logger: " << currentLogName
<< " Level: " << currentLogLevel
<< " logEntryStream = " << logEntryStream.str()
<< std::endl;
//TODO Make a log call to your logging library. You have your log level
// and a completed log entry stream.
}
// Overloaded insertion operator that adds the given parameter
// to the log entry stream.
template <typename T>
LogInputStream &operator<<(T const &value) {
logEntryStream << value;
return *this;
}
std::string currentLogName;
logLevelT currentLogLevel;
std::ostringstream logEntryStream;
};
// Overloaded function call operator for providing the log level
Logger::LogInputStream operator()(logLevelT logLevel) {
LogInputStream logInputStream(logLevel, logName);
return logInputStream;
}
// Overloaded insertion operator that is used if the overloaded
// function call operator is not used.
template <typename T>
Logger::LogInputStream operator<<(T const &value) {
LogInputStream logInputStream(INFO_LEVEL, logName);
logInputStream << value;
return logInputStream;
}
};
int main(int argc, char *argv[]) {
Logger logger1 = Logger("Logger1", "/path/to/log.log");
Logger logger2 = Logger("Logger2", "/path/to/log.log");
logger1(INFO_LEVEL) << "This is the " << 1 << "st test";
logger2(ERROR_LEVEL) << "This is the " << 2 << "nd test";
logger2 << "This is the " << 3 << "rd test";
return 0;
}
我觉得我可以在命名和评论方面做得更好,但时间紧迫。我绝对愿意接受任何评论或批评。
你必须重载 operator()
这样,它会设置内部日志级别和 return *this
作为类型 Logger&
,所以重载 operator<<
会起作用在 returned 参考中设置了必要的日志级别。
像这样:
Logger& Logger::operator()(LogLevel level) {
// set internal log level
return *this;
}