根据值对C#中具有不同标签的xelement进行排序

Sorting xelement with different tags in C# based on value

我有下面的XML需要根据值sequence标签进行排序,排序的XML放在Totals根节点,这在C#中可行吗.如果序列为空或重复,则将该标签留在原处。

<Totals sequence="001" label="Totals" tooltip="Totals">
  <ReturnTotalGrossReceipts sequence="001" datatype="Money" label="Total Receipts"  />
  <ReturnTotalAdjusts sequence="002" datatype="Money" label="Total Adjustments" />
  <ReturnTotalTaxableSales sequence="003" datatype="Money" label="Total Taxable Sales"  />
  <ReturnTotalTax sequence="005" datatype="Money" label="Total Amount of Tax" />
  <ReturnTimelyPay sequence="004" datatype="Money" label="Total Pay"  />
  <ReturnTotalSalesTaxDue sequence="006" datatype="Money" label="Total Due"  />
  <ReturnInterest sequence="006" datatype="Money" label="Interest" />
</Totals>

下面的代码应该会为您提供一个排序列表,如果序列元素为空,则将元素留在原地。

var sXml = "<Totals sequence=\"001\" label=\"Totals\" tooltip=\"Totals\"><ReturnTotalGrossReceipts sequence=\"001\" datatype=\"Money\" label=\"Total Receipts\" /><ReturnTotalAdjusts sequence=\"002\" datatype=\"Money\" label=\"Total Adjustments\" /><ReturnTotalTaxableSales sequence=\"003\" datatype=\"Money\" label=\"Total Taxable Sales\" /><ReturnTotalTax sequence=\"005\" datatype=\"Money\" label=\"Total Amount of Tax\" /><ReturnTimelyPay sequence=\"004\" datatype=\"Money\" label=\"Total Pay\"  /><ReturnTotalSalesTaxDue sequence=\"006\" datatype=\"Money\" label=\"Total Due\"  /><ReturnInterest sequence=\"006\" datatype=\"Money\" label=\"Interest\" /></Totals>";
var xml = XElement.Parse(sXml);
xml
    .Descendants()
    .Select((x, i) => new { Index = i, Element = x })
    .OrderBy(x => Convert.ToInt32(x.Element.Attribute("sequence")?.Value ?? x.Index.ToString()))
    .Select(x => x.Element);

试试这个

using System.Xml.Linq;

namespace ConsoleApplication29
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            XDocument xdoc = XDocument.Load(FILENAME);
            XElement total = xdoc.Descendants("Totals").First();


            total.ReplaceNodes(total.Elements().OrderBy(x => (int)x.Attribute("sequence")));
        }

    }

}